find the real and complex zeros of the following function f(x)=x^3-5x^2+8x-6

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# find the real and complex zeros of the following function f(x)=x^3-5x^2+8x-6

find the real and complex zeros of the following function f(x)=x^3-5x^2+8x-6

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### find the real and complex zeros of the following function f(x ...

find the real and complex zeros of the following function f(x)=x^3-5x^2 ... the following function f(x)=x^3-5x^2+8x-6. ... find real and complex zeros for f(x) x^3+5x ...

### find real and complex zeros for f(x) x^3+5x^2+17x+13 ...

f(x)=x³+5x²+17x+13 I have to find the real and complex zeros of the following function?

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### MATH 11011 FINDING REAL ZEROS KSU OF A POLYNOMIAL

MATH 11011 FINDING REAL ZEROS KSU OF A POLYNOMIAL Deﬂnitions: † Polynomial: is a function of the form P(x) ... x = ¡3 Real zeros : 2; ¡1; ¡3; 3 2 6. P(x) ...

### 2.5 zeros of polynomial functions - Utep - Academics Portal Index

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### 3.4 Complex Zeros and the Fundamental Theorem of Algebra

286 Polynomial Functions 3.4 Complex Zeros and the Fundamental Theorem of Algebra In Section3.3, we were focused on nding the real zeros of a polynomial function.

### Finding complex zeros of a polynomial function - YouTube

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### find the real and complex zeros of the following function f(x)=x^3-5x^2+8x-6

By trial and error we can see that one root is x=3 so (x-3) is a factor. Divide the polynomial by this factor and we get x^2-2x+2. Use the quadratic formula to find the remaining zeroes: x=(2+sqrt(4-8))/2=(2+sqrt(-4))/2=(2+2i)/2=1+i. So the three roots are 3, 1+i, 1-i. (I used synthetic division

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### find real and complex zeros for f(x) x^3+5x^2+17x+13

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### complex, rational and real roots

The quintic function should have 5 roots.  The changes of sign (through Descartes) tell us the maximum number of positive roots. Since there are two changes of sign there is a maximum of 2 positive roots. To find the number of negative roots we negate the terms with odd powers and check

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### Find all zeros of the function g(x)=x^3+6x^2+21x+26

Find the real and complex zeros of the following function. f(x)=x^3-6x^2+21x-26

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### find the complex and real zeros of the following function

only zero is at x=-4  y=0

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### Rational Zero Theorem?

both of your equations can be factored x^4-7x^2-144 =(x^2-16)(x^2 +9) =(x-4)(x+4)(x^2+9) giving you 4 and -4 as real roots the second one factors into (x^2-25)(x^2+1) =(x-5)(x+5)(x^2+1) giving you 5 and -5 when you have only x^4, x^2 and a constant, you can factor as above just like ax^2 +bx+c

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### find the real and complex zeros of the following function f(x)=x^3-5x^2+8x-6

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### Finding a polynomial of a given degree with given zeros: Complex zeros

If the polynomial has an even degree, meaning that the highest power of the variable (for example: x) is an even number (for example: x^4), then all the zeroes could be complex. If odd, there must be at least one real zero. A complex zero is given by the complex expression: a+ib, where a and b ar

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### f(x) =5x^4 -10X^3+X^2-2.5X+20

f(x) = 5x^4 - 10x^3 + x^2 - 2.5x + 20 because it is to the 4th power there are up to 4 roots. by Descarte's there are 4 changes from positive to negative.  So there up to 4 real roots and 2 maybe real and 2 complex. So, there may be 0 to 4 real roots. 2 maybe complex. f

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### minimun of sqrt(x^4-3x^2+4)+sqrt(x^4-3x^2-8x+20)

f = sqrt(x^4-3x^2+4)+sqrt(x^4-3x^2-8x+20) To find the turning points, differentiate f and set that value to zero. df/dx = (1/2)*(4*x^3-6*x)/sqrt(x^4-3*x^2+4)+(1/2)*(4*x^3-6*x-8)/sqrt(x^4-3*x^2-8*x+20) = 0 (4*x^3-6*x)/sqrt(x^4-3*x^2+4) = -(4*x^3-6*x-8)/sqrt(x^4-3*x^2-8*x+20) cross-multipl

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