How do I solve y=-x-4

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How do I solve y=-x-4

I need to be able to plot these points on a graph but i don't know how to solve the problem.

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SOLUTION: how to graph y=x-4? - Algebra.Com


SOLUTION: how to graph y=x-4? Algebra -> Linear-equations-> SOLUTION: ... Question 400541: how to graph y=x-4? Answer by mananth(15050) (Show Source):
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SOLUTION: y=-3x+4 y=x-4 how do u do that?


SOLUTION: y=-3x+4 y=x-4 how do u do that? ... y = -3x + 4 and y = +x - 4. One way you can do this problem is to ... x = -8/-4 = +2. Then you can solve for y by ...
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5 Ways to Solve for X - wikiHow


How to Solve for X. There are a number of ways to solve for x, ...
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How to solve [math]2x = x - 4[/math] - Quora


How do you solve [math]3^x -4 = 5^{2x} - 7[/math]? How do I solve [math]\ln(x-1) - \ln(2x) = 0[/math]? Related Questions. How do I solve [math]4^x-2^x-2=0[/math]?
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How do you solve y= x^2-4 and y= x-2? | Socratic


... (y = x^2 -4), (y = x - 2) :} we shall have x^2 -4 = x - 2 x^2 -4 ... SOCRATIC Subjects . Science Anatomy ... How do you solve #y= x^2-4# and #y= x-2#?
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How do you solve y=x+4 and y=3x? | Socratic


x=2 y=6 y=3x (1) y=x+4 (2) Subtracting (1) - (2): 0 = 2x-4 2x=4 x=4/2=2 y=3xx2=6. SOCRATIC ... How do you solve #y=x^2# and #y=1/2x+5# using substitution?
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Solve for Y video - YouTube


Oct 25, 2012 · Solve for Y video Maddie Sokolosky. Loading ... Find x and y intercepts given standard form ... How to Solve for Slope & Y-Intercept - Duration: ...

Solve for x and y : x^2-y^2=4; x+y=2 | eNotes


Get an answer for 'Solve for x and y : x^2-y^2=4; x+y=2' and find homework help for other Math questions at eNotes. ... Solve for x and y : x^2-y^2=4; x+y=2. print Print;
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Suggested Questions And Answer :


How do I solve y=-x-4

How do I solve y=-x-4 I need to be able to plot these points on a graph but i don't know how to solve the problem.   make an x & y axis. ( like a cross one line goes vertical an the other horizontal) put equal dimention for x & y line From center line moving
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how to solve for x with fractions

Simplifying x3 + 3x2 + -4x = 0 Reorder the terms: -4x + 3x2 + x3 = 0 Solving -4x + 3x2 + x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(-4 + 3x + x2) = 0 Factor a trinomial. x((-4 + -1x)(1 + -1x)) = 0 Subproblem 1 Set the factor 'x' equal to zero an
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How do you solve this problem? solve for d: n= m+3d/4

Problem: How do you solve this problem? solve for d: n= m+3d/4 I need help solving this and seeing how it was solved since I am having trouble figuring out what to do and how to solve it thanks. n = m + 3d/4 n - m = (m + 3d/4) - m n - m = 3d/4 4(n - m) = (3d/4)4 4(n - m) = 3d 4(n - m)/3 = 3
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Solve, using linear combination. 3x + y = 4 2x + y = 5

line 1: 3x+y=4    or y=4-3x line 2: 2x+y=5 line 1 -line2...(3x-2x)+(y-y)=4-5 or x=-1 y=4-3x=4+3=7
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how can i solve these equations?

how can i solve these equations? x + 3y – z = 2 x – 2y + 3z = 7 x + 2y – 5z = –21 We eliminate one of the unknowns (x, y or z, take your choice), leaving two unknowns. Then, we eliminate a second one, giving us an equation with only one of the unknowns. Solve for that and plug that value in
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Inequalities

9x+6=51 9x=51-6 9x=45 x=5
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how do you solve 3/x+5

how do you solve 3/x+5 I'm confused on how to solve this problem All you have is an expression. There is nothing to solve until you make it an equation. 3/x + 5 = -8 3/x + 5 = 14 3/x + 5 = 0 3/x + 5 = 38.67 3/x + 5 = -91 3/x + 5 = 43 Those can be solved, because they are complete. Each one will h
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x - z = -3, y + z = 9, -2x + 3y +5z = 33

Problem: x - z = -3, y + z = 9, -2x + 3y +5z = 33 1) x - z = -3 2) y + z = 9 3) -2x + 3y + 5z = 33 Add equation 2 to equation 1.      x     - z = -3 +(    y + z =  9) ------------------   x + y     = 6 4)
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how to solve by substitution

how to solve by substitution .3x+3y=1.2(100) "Substitution" implies there are TWO equations in two unknowns. You solve one of them for one of the unknowns in terms of the other, e.g., solve for y in terms of x. THEN, you substitute that value into the other equation where the y is, and yo
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2x+y=9 x-2z=-3 2y+3z=15

2x+y=9 x-2z=-3 2y+3z=15 Forgot how to do This. Problems Solving systems of this type requires eliminating all but one unknown so you can solve for that unknown. Then, plug that value into one of the equations to solve for another of the unknowns. Finally, plug both of those values into an equation
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