Finding a polynomial of a given degree with given zeros: Complex zeros

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Finding a polynomial of a given degree with given zeros: Complex zeros

need help on all this stuff please thanks so much

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Finding Polynomials with Given Zeros - Boundless

Learn more about finding polynomials with given zeros in the Boundless open textbook. ... it cannot be a zero of the polynomial we find. Degree of the Polynomial.

Finding the Formula for a Polynomial Given: Zeros/Roots ...

Aug 26, 2010 · Finding the Formula for a Polynomial Given: Zeros/Roots, Degree, and One Point - Example 1. ... Pre-Calculus - Given complex zeros find the polynomial ...

Find a Polynomial of Least Degree with Given Zeros complex ...

Jan 06, 2013 · Find a Polynomial of Least Degree with Given ... Given complex zeros find the polynomial ... How to find a polynomial of given degree with given ...

Finding General Polynomials from Their Zeroes

Finding General Polynomials ... but I'm supposed to be finding a polynomial with integer coefficients. ... The given point then gives me: a ...

Online Polynomial Roots Calculator that shows work

Online polynomial roots calculator finds the ... This online calculator finds the roots of given polynomial. For Polynomials of degree ... (zeros) of the polynomial ...

Algebra 2 - Finding Complex Zeros of a Polynomial Function ...

How to find complex zeros of a polynomial function. ... How to find a polynomial of given degree with given complex zeros How to find a polynomial of given degree ...

Using Rational & Complex Zeros to Write Polynomial Equations ...

... Using Rational & Complex Zeros to Write Polynomial ... of polynomial functions of degree 3 ... given a set of rational and/or complex zeros;

2.5 zeros of polynomial functions - Utep - Academics Portal Index

• Find rational zeros of polynomial functions. • Find conjugate pairs of complex zeros. ... Example 6 – Finding a Polynomial with Given Zeros

Algebra - Finding Zeroes of Polynomials - Lamar University

Finding Zeroes of Polynomials ... In general, finding all the zeroes of any polynomial is a fairly ... until we reach a second degree polynomial.

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Finding a polynomial of a given degree with given zeros: Complex zeros

If the polynomial has an even degree, meaning that the highest power of the variable (for example: x) is an even number (for example: x^4), then all the zeroes could be complex. If odd, there must be at least one real zero. A complex zero is given by the complex expression: a+ib, where a and b ar

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find a polynomial function of the lowest degree with rational coefficients that has the given numbers as some of its zeros -3i,5

find a polynomial function of the lowest degree with rational coefficients that has the given numbers as some of its zeros -3i,5 You have a complex root, x = -3i Now the thing about complex roots is that they always come in pairs, as complex conjugates. If one complex root is (a + ib), the

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3+i, 3 Lowest Degree

Question: 3+i, 3 Lowest Degree. Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. When a polynomial has complex roots, they always come as a pair. So if x = 3+i is one root, then x = 3 - i is another root. (Two complex ro

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Use the given zero to find the remaining zeros. h(x)=3x^4+10x^3+19x^2+90x-73 zero:-3i

Use the given zero to find the remaining zeros. h(x)=3x^4+10x^3+19x^2+90x-73 zero:-3i There’s an error in your quartic. It should be: h(x)=3x^4+10x^3+19x^2+90x-72 You are given that one of the zeros is -3i. i.e. one of the factors is (x + 3i) If a polynomial has a complex factor, or ro

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form a polynomial function with real coefficients given the degree and zeros

f(x)=(x+5)(x-4-3i)(x+a+ib) represents the function with an added unknown complex factor. We need to find a and b to identify the third zero. We know that f(x)=91 when x=2, so we can write 91=7(-2-3i)(2+a+ib). That is: -13=(2+3i)(2+a+ib)=4+2a+2ib+6i+3ia-3b. There is no complex component in the

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form a polynominal f(x) with real coefficients given the following degree 5; zeros: -7;-i;-3+i

The missing complex zeroes are i and -3-i, because they will "cancel out" the given complex zeroes. The polynomial f(x)=(x+7)(x^2+1)(x^2+6x+10)=a(x^5+13x^4+53x^3+83x^2+52x+70), where a is a real number.

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how i solve this f(x)=0.3582*x^2 - 3.3833 * x + 9.0748 by matlab

how i solve this f(x)=0.3582*x^2 - 3.3833 * x + 9.0748 When asked to solve f(x) = 0, that means find the value(s) of x that, when substituted into the expression for f(x) will make it equal to zero. So, to find f(x) = 0, then we set 0.3582*x^2 - 3.3833 * x + 9.0748 = 0. This is a quadratic

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given 3i is a zero of P(x)=x^4-3x^3+19x^2-27x+90 find all other zeros

given 3i is a zero of P(x)=x^4-3x^3+19x^2-27x+90 find all other zeros Complex roots always come in pairs, as complex conjugates. One root is 3i, i.e. x = 0 + 3i. The complex conugate of this root is x = 0 - 3i. So the two roots are x = 3i, x = -3i. Then two factors of the polynon

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Form a polynomial f(x) with real coefficients given the following degree 5; zeros: - 3 ,- i ; -6 + i

We need two more zeroes to make the polynomial degree 5 and to cancel out the two complex zeroes: i and -6-i. So the polynomial becomes (x-i)(x+i)(x+6+i)(x+6-i)(x+3)=(x^2+1)(x^2+12x+37)(x+3)= (x^3+x+3x^2+3)(x^2+12x+37)= x^5+12x^4+37x^3+x^3+12x^2+37x+3x^4+36x^3+111x^2+3x^2+36x+111=

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find a third degree polynomial equation with rational coefficients that has roots -4 and 6+i

A cubic equation always has three roots. These three roots are: 1) three real roots or, 2) 1 real root and two complex roots If one of the two complex roots is a + ib, then the other complex root is a - ib. We are given two of the roots as -4 and 6+i. Since one of the roots is c