solve 3/4x=6/7

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Guide :

# solve 3/4x=6/7

how to you solve for x, when 3/4x=6/7

## Research, Knowledge and Information :

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### Solve Equation with Steps Step-by-Step Math Problem Solver

Equations such as x + 3 = 7 are ... we use the addition-subtraction property and the division property to solve an equation. Example 3 Solve 4x + 7 ... 4x + 7 - x - 7 ...

### How to solve 3 [(2x + 7) + 9] = 7 (4x + 6) - Quora

How do I solve 3 [(2x + 7) + 9] = 7 (4x + 6)? Update Cancel. ... How do I solve this: 9+3/4+7+2/17-9+1/? How can I solve this equation: [math]7^{2x+1}-2(7)^{x+1} =-7 ...

### How to solve 4/4x-3= -6 - Quora

Multiply both sides by (4x-3): 4 = -6 (4x-3) then multiply: 4 = -24 ... How do you solve [math]6x^4+x^3+10x^2+6=0[/math]? How do you solve [math]x^4-x^3-x^2-5x+6=0 ...

### How do you solve 6x-3=4x+7? | Socratic

x=5 >6x-3=4x+7 Add minus -4x on both sides 6x-3-4x=4x+7-4x 6x-3-4x=cancel(4x)+7cancel(-4x) ... How do you solve #6x-3=4x+7#? Algebra. 1 Answer

### Solving equations using logs - mathcentre.ac.uk

Solving equations using logs ... Solve the equation log 2 (4x+3) = 7. Solution Writing the equation in the alternative form using powers we ﬁnd 27 = 4x+3 from which x =

### How do you solve and graph 3[4x-(2x-7)]<2(3x-5)? | Socratic

... 3[4x-(2x-7)] < 2(3x-5) First, simplify both the left and right sides: color(white)("XXX ... How do you solve and write the following in interval notation: #(x-5) ...

### 6-5(2x-3)=4x+7 - solution - GetEasySolution.com

Simple and best practice solution for 6-5(2x-3)=4x+7 equation. Check how easy it is, ... 21 + -10x = 7 + 4x Solving 21 + -10x = 7 + 4x Solving for variable 'x'.

### 1. Solve the inequality -3/4x + 6 &gt; -3. x &gt; -2 x &lt ...

1. Solve the inequality -3/4x + 6 > -3. x > -2 x < -2 x > 12 x < 12 2. ... What steps should be followed to solve the inequality -4x < 8. Multiply by -4 on each side ...

## Suggested Questions And Answer :

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### How do I solve y=-x-4

How do I solve y=-x-4 I need to be able to plot these points on a graph but i don't know how to solve the problem.   make an x & y axis. ( like a cross one line goes vertical an the other horizontal) put equal dimention for x & y line From center line moving

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### how to solve for x with fractions

Simplifying x3 + 3x2 + -4x = 0 Reorder the terms: -4x + 3x2 + x3 = 0 Solving -4x + 3x2 + x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(-4 + 3x + x2) = 0 Factor a trinomial. x((-4 + -1x)(1 + -1x)) = 0 Subproblem 1 Set the factor 'x' equal to zero an

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### How do you solve this problem? solve for d: n= m+3d/4

Problem: How do you solve this problem? solve for d: n= m+3d/4 I need help solving this and seeing how it was solved since I am having trouble figuring out what to do and how to solve it thanks. n = m + 3d/4 n - m = (m + 3d/4) - m n - m = 3d/4 4(n - m) = (3d/4)4 4(n - m) = 3d 4(n - m)/3 = 3

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### Solve, using linear combination. 3x + y = 4 2x + y = 5

line 1: 3x+y=4    or y=4-3x line 2: 2x+y=5 line 1 -line2...(3x-2x)+(y-y)=4-5 or x=-1 y=4-3x=4+3=7

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### how can i solve these equations?

how can i solve these equations? x + 3y – z = 2 x – 2y + 3z = 7 x + 2y – 5z = –21 We eliminate one of the unknowns (x, y or z, take your choice), leaving two unknowns. Then, we eliminate a second one, giving us an equation with only one of the unknowns. Solve for that and plug that value in

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### Inequalities

9x+6=51 9x=51-6 9x=45 x=5

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### how do you solve 3/x+5

how do you solve 3/x+5 I'm confused on how to solve this problem All you have is an expression. There is nothing to solve until you make it an equation. 3/x + 5 = -8 3/x + 5 = 14 3/x + 5 = 0 3/x + 5 = 38.67 3/x + 5 = -91 3/x + 5 = 43 Those can be solved, because they are complete. Each one will h

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### x - z = -3, y + z = 9, -2x + 3y +5z = 33

Problem: x - z = -3, y + z = 9, -2x + 3y +5z = 33 1) x - z = -3 2) y + z = 9 3) -2x + 3y + 5z = 33 Add equation 2 to equation 1.      x     - z = -3 +(    y + z =  9) ------------------   x + y     = 6 4)

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### how to solve by substitution

how to solve by substitution .3x+3y=1.2(100) "Substitution" implies there are TWO equations in two unknowns. You solve one of them for one of the unknowns in terms of the other, e.g., solve for y in terms of x. THEN, you substitute that value into the other equation where the y is, and yo

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### 2x+y=9 x-2z=-3 2y+3z=15

2x+y=9 x-2z=-3 2y+3z=15 Forgot how to do This. Problems Solving systems of this type requires eliminating all but one unknown so you can solve for that unknown. Then, plug that value into one of the equations to solve for another of the unknowns. Finally, plug both of those values into an equation

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