line LN with midpoint M, LM=x+9, MN=4x...trying to find LN

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# line LN with midpoint M, LM=x+9, MN=4x...trying to find LN

there is a line LN with midpoint M, LM=x+9 and MN=4x... trying to find LN.

## Research, Knowledge and Information :

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### Line LN has a midpoint M; LM=7x+3, and LN=64. find x and LM

Find x and LM if M is the midpoint of line LN, LM=7x-3, and LN=64. ... line LN with midpoint M, LM=x+9, MN=4x...trying to find LN. asked Dec 9, 2013 in ALGEBRA 2 by ...
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### If m is the midpoint of LN and LN=27.8 , find the length of MN?

If m is the midpoint of LN and LN=27.8 , find the length of MN? ... If m is the midpoint of LN and LN=27.8 , find the length of MN? Answer for question: Your name:

### M is midpoint of a segment LN. if LM=3x+16 and MN=7x, how ...

M is midpoint of a segment LN. if LM=3x+16 ... LM = MN 3x+16 = 7x 16 = 4x x = 4 LN = LM+MN = 3x+16+7x = 10x+16 ... there is a line LN with midpoint M, LM=x+9 and MN ...

### Point M is between points L and N and line LN. LN=6x, LM=4x+8 ...

Point M is between points L and N and line LN. LN=6x, LM=4x+8, and MN=27.solve for x and find LN. ... 2017 Wyzant, Inc.
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### M is the midpoint of LM LM=3x+5 LN=5x+40 Find MN I've tried ...

Geometry M is the midpoint of LM LM=3x+5 LN=5x+40 Find MN I've tried to work this out several times and am pretty sure I start it off by 3x+5=5(x)+40 but I keep ...
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### Distance and Length KEY

Distance and Length KEY Using the given line segments ... x? 9 14. If KL = 4x – 1, LM = 2x – 1, and KM = 2x, what is the value of x? 0.5 15. If L is the midpoint ...
Read More At : www.nederland.k12.tx.us...

## Suggested Questions And Answer :

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### If M is the midpoint of segment AB, find the coodinates of B; given that A = (-8,9) and M= (-6,6).

Midpoint of a line is the average of the coords of the end points. If B is (x,y) then (x-8)/2=-6 and (y+9)/2=6, and x=-12+8=-4 and y=12-9=3. B is (-4,3). The midpoint of (16,-4) and (-2,-76) is (7,-40), being the average of the endpoint coords. The slope of the segment is (-76+4)/(-2-16)=-72/(-18

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### Find the equation of the: a) tangent to the circle with center (-1,2) at the point (3,1) b) perpendicular bisector bisector of (AB) for A (2,6) and B(5,-2).

Problem: Find the equation of the: a) tangent to the circle with center (-1,2) at the point (3,1) b) perpendicular bisector bisector of (AB) for A (2,6) and B(5,-2). I  need help. a) Any line that is tangent to the circle has a slope that is    the negative inverse of the slope

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### In a triangle ABC, line joining orthocenter and the circumscenter is parallel to AC, then find tanA *tanC.

Draw the base of the triangle AC and mark its midpoint, D. Draw a perpendicular from D. Somewhere along the perpendicular will be the circumcentre, that is, the centre of the circle that circumscribes the triangle ABC.  The position of vertex B has to be such that the perpendicular bise

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### I need to find the midpoints of each side of the triangles. and draw perpendicular bisectors

1. if 2 lines be perpendikular (90 deg apart), slope2=-1/slope1 2. yer 3 points...triangel hav sidle lengths av 11.661904, 17,888544, & 20,59126 angels =34.38035, 94.39871, 51.22094  degrees sampel side...from (-10,-8) tu (-2,8)...deltax=8, deltay=16, slope=deltay/deltax=16/8=2 perp lin

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### in triangle ABC X is midpoint of side AB.Y is the midpoint of CX.let by cut AC at Z.show that AZ=2ZC

To tackle this problem I decided to try using a graph. Point A of the triangle is at the origin (0,0); point B is at (2X,0) and point X at (X,0), so that X is the midpoint of AB. The third point of the triangle at C is (a,b), an arbitrary point. We know that Y is halfway along CX so that means Y is

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### X is midpoint side AB in triangle ABC.y is the midpoint of CX.let by cut AC at Z.show that AZ=2ZC

To tackle this problem I decided to try using a graph. Point A of the triangle is at the origin (0,0); point B is at (2X,0) and point X at (X,0), so that X is the midpoint of AB. The third point of the triangle at C is (a,b), an arbitrary point. We know that Y is halfway along CX so that means Y is

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### M(0,1) is the midpoint between R(x,y) and S(9,6). Find the coordinates of R.

1 end av a strate line=(9,6) midpoint=(0,1) tu find other end av line midx=0, so xleft=-9 midy=1, so (6+yleft)/2=1, or (6+yleft)=2, so yleft=-4 left end av line=(-9,-4)

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### What is the coordinates of point S if Tis (0,4) and the midpoint is (5,-8)

me assume yer ramblings tri tu impli yu hav a strate line tween 2 points... 2 points=(0,4) & (5, -8)... Then yu impli point 2=midpoint av a line yu wanna find... deltax=5, deltay =-12... tu extend line same distans, add same numbers tu point 2... thus, point 3=(5+5, -8-12)=10, -20)

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### line LN with midpoint M, LM=x+9, MN=4x...trying to find LN

lm=x+9 impli a strate line with slope=1 (angel=45 deg) and y-intersept=9, non if oenlee no how long the line is ??? mn=4x ??? iz this spozed tu impli mid point at x=4 ????

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### Find the midpoint of the line segment joining the points (-3,1) and (5,4)

find midpoint av line tween 2 points...(-3,1) & (5,4) averaej x=(5-3)/2=2/2=1 averaej y=(4+1)/2=5/2=2.5 midpoint=(1, 2.5)

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