1=2x(x-2)-[5-2x(1-y)]

Guide :

1=2x(x-2)-[5-2x(1-y)]

1=2x(x-2)-[5-2x(1-y)]

Research, Knowledge and Information :


How do you solve Y=2x^2-3 and Y=3x-1? | Socratic


... (y-5)=0 =>(2y+5)(y-5) =>y=-5/2,y=5 Substitute these into equation (3) x=(-5/2+1)/3=-1/2," "x=(5+1) ... SOCRATIC Subjects . Science Anatomy ...
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2x + y = 1, x^2 + y^ 2 = 1 (260635) | Wyzant Resources


2x + y = 1 x^2 + y^2 = 1 (This is the Unit Circle for Trig.) x^2 + (1 ... 5x^2 - 4x = 0 x(5x - 4) = 0 x = 0 or x = 4/5 y = 1 or y = 1 - 2(4/5) = -3/5 Solutions are (0 ...
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(2x-5)(x+1)=2 - solution - Get Easy Solution


... (-5 + 2x)(x + 1) = 2 Reorder the terms: (-5 + 2x)(1 + x) = 2 Multiply (-5 + 2x) * (1 + x) (-5(1 + x) + 2x * (1 + x)) = 2 ((1 * -5 + x * -5) + 2x * (1 + x)) = 2 ...
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What is the vertex of y=1/2x^2+x-2? | Socratic


... (-1, -2.5) Given the equation of a parabola, y = ax^2 + bx + c, ... What is the vertex of #y=1/2x^2+x-2#? ... (x^2+2x+5) dx by using ...
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Suggested Questions And Answer :


How do you do proper form and improper form of a 5 digit #

When you add up the numbers you get 50000+14000+700+10+2=64712. However I think the tens figure should have been 5*10 not 1*10, otherwise the answer is none of (a) to (d). If this adjustment is made the number is 64752. So answer d would be the right one. Note how the thousands figure spills ov
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what are the two tangent lines of x^2 and -x^2+2x-5

y=x^2, dy/dx=2x; y=-x^2+2x-5, dy/dx=-2x+2. These are the tangents at (x,y) for each equation, to find the tangent lines, you need to know at which point the tangent line is required, because it varies from point to point so I'm guessing that since you want two tangent lines, the two tangent lines to
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Given that 1/Z = 1/Z1 + 1/Z2, obtain an explicit expression for R and X in terms of R1, R2, X¬1, X2.; where Z = R + Xi, Z1 = R1 +X1i, Z2 = R2 +X2i

This could take a little time, so I'll probably split the answer up into segments. Z=Z1Z2/(Z1+Z2)=R+iX, so R is the real component and X the imaginary. Z1Z2=(R1+X1i)(R2+X2i)=R1R2-X1X2+i(R1X2+R2X1)=A+iB where A=R1R2-X1X2 and B=R1X2+R2X1. Z1+Z2=R1+R2+i(X1+X2)=C+iD where C and D are the real a
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howto write an equation of the sine function with amplitude 0.8 and period is pi

f(x)=0.4sin(2x) has an amplitude of 0.8 because sin varies between -1 and 1, f(x) varies between -0.4 and 0.4 the difference being 0.8 which is the height of the sine wave. The period of sine is 2(pi), when x2=x1+(pi) sin(2x2)=sin(2x1) because sin(2x2)=sin(2(x1+(pi))=sin(2x1+2(pi))=sin(2x1).
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or book in informston

yu got 2 many amps theer...gonna blo a fuze
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is there a solution to (a) x1 + 2x2 + 3x3 = 1 2x1 + 3x2 + 4x3 = 3 x1 + 2x2 + x3 = 3

Matrix format (Gauss method): ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 1 2 1 | 3 ) R3-R1: ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 0 0 -2 | 2 ) R3/-2: ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 0 0 1 | -1 ) R2-R1: ( 1 2 3 | 1 ) ( 1 1 1 | 2 ) ( 0 0 1 | -1 ) R1⇔R2: ( 1 1 1 | 2 ) ( 1 2 3 | 1 ) ( 0 0 1 | -1 ) R2-R1:
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what is 42.257 written in expanded form?

42.257 in expanded form: 40 + 2 + 0.2 + 0.05 + 0.07 42.257 in expanded form with exponents: 4*10^1 + 2*10^0 + 2*10^(-1) + 5*10^(-2) + 7*10^(-3)
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Idot know how to help my soon

u mean 1.   3x10=(2x10)+(1x 10) 2.   2x6 =(2x5)+(2x1) 3.   4x7=(4x5)+(4x2) 4.   11x8=(11x5)+(11x3) 5.   3X6=(3X1)+(3X5) 6.   6X6=(6X2)+(6X4) 7.   7X7=(7X4)+(7X3) 8.   1X8=(1X5)+(1X3)
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solve: (12 - 6) - (2x1) / 2 + (4 + 8) =


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Solve by Gauss-Jordan elimination (a) x1 + 2x2 + 3x3 = 1 2x1 + 3x2 + 4x3 = 3 x1 + 2x2 + x3 = 3

Matrix format: ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 1 2 1 | 3 ) R3-R1: ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 0 0 -2 | 2 ) R3/-2: ( 1 2 3 | 1 ) ( 2 3 4 | 3 ) ( 0 0 1 | -1 ) R2-R1: ( 1 2 3 | 1 ) ( 1 1 1 | 2 ) ( 0 0 1 | -1 ) R1⇔R2: ( 1 1 1 | 2 ) ( 1 2 3 | 1 ) ( 0 0 1 | -1 ) R2-R1: ( 1 1 1 | 2 )
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