how do you solve for m in equation x(m+8)+y(m-5)=z(m-4) if x+y-z doesnt equal 0

Guide :

how do you solve for m in equation x(m+8)+y(m-5)=z(m-4) if x+y-z doesnt equal 0

solve for m

Research, Knowledge and Information :

Solving square-root equations (basic) (video) | Khan Academy

We're asked to solve for x. So we have the square root of the entire quantity 5x squared minus 8 is equal to 2x. Now we already have an expression under a radical ...
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Solving Quadratic Equations by Factoring | Purplemath

... " before we make any attempt to solve the quadratic equation by ... So I'll set the factors equal to 12 and solve to get x = 10 and x = 9 ... Solve x 2 – 4 = 0.
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Equation - Wikipedia

Linear equations have the form ax + b = 0, where a and b are parameters. To solve ... are equal, the scale balances ... coordinates x and y satisfy the equation x 2 ...
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3 Ways to Solve Two Step Algebraic Equations - wikiHow

How to Solve Two Step Algebraic Equations. ... To solve a two step algebraic equation, all you have to do is ... If there is no number following an x, assume it is x + 0.
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Systems of Linear Equations - Math Is Fun

Systems of Linear Equations . ... Solve these two equations: x + y = 6 ... Anywhere on that line d is equal to 0.2t. at t=5 and d=1, the equation is true ...
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SparkNotes: Quadratics: Graphing Parabolas

A summary of Graphing Parabolas in 's Quadratics. ... Graphing y = x 2. We have ... starting with x = 0, y increases by 1, 3, 5, 7, …. As x ...
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The Slope of a Straight Line | Purplemath

The Slope of a Straight Line. ... plug them into the line equation, and solve for each corresponding y-value. If, ... If you think I'm wrong, ...
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Suggested Questions And Answer :

How do I solve for "w" and (1-w) in equation w x 2.5907 + (1-w) x 1.9234

How do I solve for "w" and (1-w) in equation w x 2.5907 + (1-w) x 1.9234 I need to solve for w and then (1-w) That is NOT an equation, it is only an expression. Notice that there is no equal sign and no value that the expression is equal to. Until we have a complete equation, there is no
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solve for x when (.182+x)/(.106-2x)=3.24

solve for x when (.182+x)/(.106-2x)=3.24 Im trying to solve for x its for a chemistry equation but i need to solve for x using the quadratic equation and i dont know which equals a b and c to find x. ************************** You can't solve this with the quadratic formula, because there is no x^2
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how do you solve an equation with an equal sign with a slash through the middle

The equal sign with a slash through it means "not equal to." 2 + 7 ≠ 10    Two plus seven is not equal to ten. As for how to solve the equation, it depends on what the equation is, what it represents.
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how to solve for x with fractions

Simplifying x3 + 3x2 + -4x = 0 Reorder the terms: -4x + 3x2 + x3 = 0 Solving -4x + 3x2 + x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(-4 + 3x + x2) = 0 Factor a trinomial. x((-4 + -1x)(1 + -1x)) = 0 Subproblem 1 Set the factor 'x' equal to zero an
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how to solve this system of equations using substitutioin: -4x+y=6, -5-y=21

- 4x + y = 6 - 5x - y = 21   To do this we need to rearrange one of the equations. It doesn't matter which one you choose to rearrange but I will choose the first.    - 4x + y = 6 Let's add '4x' to both sides of the equation so that we have an equation in the
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sqrt(3a+10) = sqrt(2a-1) + 2

sqrt(3a+10)=sqrt(2a-1)+2 To remove the radical on the left-hand side of the equation, square both sides of the equation. (~(3a+10))^(2)=(~(2a-1)+2)^(2) Simplify the left-hand side of the equation. 3a+10=(~(2a-1)+2)^(2) Squaring an expression is the same as multiplying the expression by itself 2 t
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2x=3(x-4)=2(x-3) How can I solve this? You can't. Even though it is possible to string together multiple equalities, that requires ALL of them to be equal. In this string, the second may in fact be considered to be equal, and you could use the first and second quantities to calculate a value for x.
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i need the answer for these questions

Part 1 Newton’s Method for Vector-Valued Functions Our system of equations is, f1(x,y,z) = 0 f2(x,y,z) = 0 f3(x,y,z) = 0 with, f1(x,y,z) = xyz – x^2 + y^2 – 1.34 f2(x,y,z) = xy –z^2 – 0.09 f3(x,y,z) = e^x + e^y + z – 0.41 we can think of (x,y,z) as a vector
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solve the system: 5x-10y+4z=-73; -x+2y-3z=19; 4x-3y=5z=-42

solve the system: 5x-10y+4z=-73; -x+2y-3z=19; 4x-3y=5z=-42 1)  5x - 10y + 4z = -73 2)  -x +  2y - 3z =  19 3)  4x -  3y + 5z = -42 Equation three had "=5z" so I changed the equal sign to a plus sign. It happens a lot; the shift key doesn't register, so what w
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Y=-4X+3 AND 4Y + X =-1

Not quite sure what you want me to do with these, but i will solve for y in both cases. Then set them equal to eachother and solve for the variables. y = -4x + 3 4y + x = -1 Must get this into y= form. 4y = -x -1           Now we can set the two equations eq
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