what are all the numbers using numbers 4-60 divisible by 4?

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# what are all the numbers using numbers 4-60 divisible by 4?

my teacher told me to do p.13 problems 4-60. and he only wants the ones that are divisble by 4. help

## Research, Knowledge and Information :

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### The Math Dude : How to Tell If a Number is Divisible by 4, 5 ...

... the fact that a number is divisible by 4 simply means that the remainder when it’s divided by 4 is ... of course, that all of these numbers are divisible by 4.

### Divisibility Rules: How to test if a number is divisible by 2 ...

Examples of numbers that are divisible by 4 . Number Explanation 112: ... and we know that 100 is divisible by 4 so all that matters here is whether or not 24, ...

### Divisibility rule - Wikipedia

The result must be divisible by 12. 324: 32 × 2 − 4 = 60 = 5 ... then the original number is divisible by 4) Divisibility by 5 ... in that all such numbers are ...

### How many numbers are divisible by 3, 4 or 5 from 0 to 100 ...

... that is divisible by 3, 4, and 5 (which are all co-prime) is 3*4*5 = 60. ... How many 4-digit numbers divisible by 4 can be formed from the digits: ...

### How many five digit numbers that are divisible by 4 can be ...

The last two digits of all the numbers should be divisible by 4. So the last two digits can be 04 12 16 20 24 32 36 40 52 56 60 64. There are 4 cases wherein the last ...

### What Numbers Can We Make? : nrich.maths.org

Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? ... or What Numbers Can We Make Now? ...

### Factors and Divisibility - Quia

Factors and Divisibility ... 4. 60 5. 45 6. 423 7. 5,170 8. 7,536 9. 9,000 ... Cross out all the numbers divisible by 3 since they are not prime.

### sequences and series - Sum of digits of all 4-digit numbers ...

Sum of digits of all 4-digit numbers divisible by 7. ... {10,80\}), (6,\{20,90\}), (2,\{30\}), (5, \{40\}), (1,\{50\}), (4,\{60\})\$\$ There are 10 decimal digits.

### Section 4-1 Divisibility Even and Odd Numbers

Section 4-1 – Divisibility Even and Odd Numbers: ... A whole number is divisible by 4 if and only if the two rightmost digits ... Find GCD (24, 60) and LCM (24 ...

### Divisibility Rules - Math Goodies

Divisibility is a good way to factor large numbers. Learn to test for divisibility by 2, 3, 4, 5, 6, 8, 9, ... 225 is not divisible by 4 since 25 is not divisible by 4.

## Suggested Questions And Answer :

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### 10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into

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### Place the digits 1 through 9 into the grid at right so that each row forms a three-digit composite number and each column forms a three-digit prime number.

3-digit prime numbers must end in 1, 3, 7 or 9. This means the last row will be a 3-digit composite number consisting of 3 of these 4 digits. So the possibilities of the digits (in numerical order) are: 137, 139, 179, 379. The composite number must consist of one of these combinations of digits. 137

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### With using the following #'s 56,27,04,17,93 How do I find my answer of 41?

Let A, B, C, D, E represent the five numbers and OP1 to OP4 represent 4 binary operations: add, subtract, multiply, divide. Although the letters represent the given numbers, we don't know which unique number each represents. Then we can write OP4(OP3(OP2(OP1(A,B),C),D),E)=41 where OPn(x,y) represent

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### hpw do you estimate an answer to a problem with a remainder?

The purpose of the estimate is not to get an accurate answer, but just an indication of what the answer should be approximately, so that when the actual answer is determined, you can compare it with the estimate. They should be fairly close. If they are, this gives you confidence in your a

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### is the ten digit no. pqrstu8672 divisible by 32 ?

Not necessary. Note that 1111118672 is a ten digit number ending with 8672, but it is not divisible by 32. For such questions, the best (and honestly speaking, only) way is to use trial and error. Try using numbers which you believe (or suspect) will lead to failure in satisfying the given conditi

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### explain complex number and vectors

Start with real numbers. A number line is often used to represent all real numbers. It has infinite length and somewhere we can mark zero, dividing positive numbers (on the right of zero) and negative numbers (on the left of zero). The line is continuous so no real number can be left out. A line is

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### brett rode his bicycle 4/8 of a mile on saturday.Mike rode his bicycle 3/6 of a mile on saturday Who rode their bike farther Prove your answer using number lines

Both fractions are 1/2. Use two number lines, one over the other. The lines are the same length representing 1 mile. Divide the top line into equal divisions of 8 and the other into equal divisions of 6. 4 divisions of the top line and 3 of the bottom coincide. Neither rode farther than the other; t

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### solve equation 6x+5y=0, 3x-2y = 19

Exponents Exponents are supported on variables using the ^ (caret) symbol. For example, to express x2, enter x^2. Note: exponents must be positive integers, no negatives, decimals, or variables. Exponents may not currently be placed on numbers, brackets, or parentheses. Parentheses and Bracket

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### find the sum of a digits. is the number divisible by 3? 531

When we add up the digits of a number and the result is divisible by 3, then the number is divisible by 3. If, when we add the digits together we end up with a double digit number, we add the digits again and see if the result is divisible by 3. If it is, then so is the number. So 555 is divisible b

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### using only 23478 write two factors that when rounded equal 37,000.

No solution. We can't use only 2, 3, 4, 7, and 8 to make two factors that, when multiplied together, equal 37,000. 37,000 has, as one of its factors, 5.  There is no factor of 5 in 2, 3, 4, 7, or 8.  Since all numbers divisible by 5 must end in 0 or 5 and since 2, 3, 4, 7, and 8 don't co

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