What is the slope of a line that is perpendicular to (4, -1) and (-3, 5)?

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# What is the slope of a line that is perpendicular to (4, -1) and (-3, 5)?

what is the slope of a line that is perpendicular to (4, -1) and (-3, 5)

## Research, Knowledge and Information :

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### Slopes and Equations of Lines - University of Missouri–St ...

Slopes and Equations of Lines Some ... the slope of a line: The slopes of perpendicular lines are ... Example 4 What is the equation of a line with slope 3/4 and y ...

### Algebra Examples | Linear Equations | Finding the Slope of a ...

Algebra Examples. Step-by-Step ... Linear Equations. Find the Slope of a Perpendicular Line. Rewrite in ... American Express security codes are 4 digits located on ...

### Horizontal and Vertical Lines | Purplemath

The second line's equation was y = –2 x + 3, and the line's slope was m = –2. ... From the line's graph, I'll use the (arbitrary) points (4, 5) and (4, –3 ...

### Slope of a line

Slope of a line explained,videos,practice quizzes.The slope is a measure of how the line ... Perpendicular are two lines that intersect and create right 90 degree ...

### The slope of a line is 1/3 . What is the slope of a line ...

The slope of a line is 1/3 . What is the slope of a line ... perpendicular is opposite and reciprocal slope of a line is 1/3 so slope of a line perpendicular is ...

### Slope of Parallel and Perpendicular Lines - AlgebraLAB

Slope of Parallel and Perpendicular Lines: ... The parallel line will have the same slope which is 5. The perpendicular line will have a slope of which is the ...

### Finding Parallel and Perpendicular Lines - Maths Resources

Parallel and Perpendicular Lines. How to use Algebra to find parallel and perpendicular lines. ... So the perpendicular line will have a slope of 1/4: y − y 1 = ...

### in slope intercept form how would you find perpendicular line ...

in slope intercept form how would you find perpendicular line to y=3/4x+1 and goes ... and m is the slope of the perpendicular line (which is -4/3); plug in these ...

### Perpendicular Lines 1 | Coolmath.com

Perpendicular Lines. ... These lines are perpendicular. (They form a angle.) So, what's ... Finding the Slope of a Line from the Graph.

## Suggested Questions And Answer :

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### Are the two lines parallel, perpendicular, or neither?

a) The slopes (-1 and 1) have turned over fractions (1/1 vs 1/1) and their + - signs are switched, so these lines are perpendicular. b) y = 0x - 5 4x - 3y = 12 -3y = -4x + 12 y = (4/3)x - 4 0 and 4/3 are different, so the lines aren't parallel. 0 and 4/3 aren't turned over fractions of each o

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### how do you find the slope of a line sagment?

how do you find the slope of a line sagment? you are given two points which define a line segment. Find the slope of the line sagment, and then use this slope to write the equation of a parallel line [and a] perpendicular line which pass through the new y-intercept 1. line segment (1,8) and (7,-4)

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### how do you find the slope of a perpendicular line?

how do you find the slope of a perpendicular line? Presumably you know the slope of the other line, the one this line is perpendicular to. Given that the slope of that line is m, the slope of the perpendicular line is -1/m.

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### Parallel and Perpendicular Lines matching exercise

starte line...x-3y=9 bekum 3y=x-9, or y=(x/3)-3... slope=(1/3)... perpendikular line hav slope=-3

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### Give the slope-intercept form of the equation of the line that is perpendicular to and contains (-1, 9)

Start by solving for y to get this in y=mx+b form subtract 5x from both sides 4y=-5x+4 divide by 4 y=4/5x+4/4 simplify to y=4/5x+1 Now you know that the slope of the first line is 4/5 The slope of the second line is -4/5 so the second equation is y=-4/5x+?

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### Find the equation of the cylinder having its base the circle

When z=1, x^2+y^2=4, which is a circle, centre at the origin and radius 2. x-2y=1 is a plane intercepting the x-y plane with y intercept=-1/2 and x intercept=1. The equation x^2+y^2+(z-1)^2=4 is a sphere, centre (0,0,1) and radius 2. The plane cuts through the sphere when (1+2y)^2+y^2=4; 1+4y+4y^2+y

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### Find the equation of the: a) tangent to the circle with center (-1,2) at the point (3,1) b) perpendicular bisector bisector of (AB) for A (2,6) and B(5,-2).

Problem: Find the equation of the: a) tangent to the circle with center (-1,2) at the point (3,1) b) perpendicular bisector bisector of (AB) for A (2,6) and B(5,-2). I  need help. a) Any line that is tangent to the circle has a slope that is    the negative inverse of the slope

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### What is the equation of a line that passes through (2, -1) and is perpendicular to the line 2x-y=1

first step:  find slope of line 2x - y = 1 2x = y + 1 y = 2x - 1 slope of line:  2 perpendicular to slope of line:  - 1/2 now we want the equation of the line passing through (2, -1) with slope = -1/2 y - y1 = m (x - x1)  (point-slope form) y - -1 = (-1/2) (x -2) y + 1 =

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### What is the slope of a line that is perpendicular to (4, -1) and (-3, 5)?

slope of the line with points (4,-1) and (-3,5) slope = (5 - -1)/(-3 -4) slope = 6/-7 slope = -6/7 since the product of gradients of perpendicular lines is -1 . then m x -6/7 = -1 where m is the gradient of the required lined therefore m = 7/6 therefore the slope is 7/6

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### if two straight lines are perpendicular to the same line prove that they are parallel to each other

First line's slope = m Middle line (perpendicular to first line) has slope = -1/m  (change sign and flip fraction) Second line is perpendicular to middle line, so we take the slope of the middle line (-1/m) and change the sign and flip the equation, so it becomes +m/1 or just m. The first li

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