if the volume is 357 what is the length, height width

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# if the volume is 357 what is the length, height width

cant find what length height and width

## Research, Knowledge and Information :

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### Length, Width & Height to Volume Calculator - SensorsONE

This is the volume of the rectangular shaped box which corresponds to the dimensions entered for length, width and height. The volume ... Length, Width & Height to ...

### How to Calculate Your Volume - Mendocino County, CA

How to Calculate Your Volume Length X Width X Height = Volume 3 feet X 3 feet X 3 feet = 27 cubic feet 27 cubic feet = 1 cubic yard Example : 5 feet X 8 feet = 40 ...

### Conversion of Volume - Math is Fun

Conversion of Volume. ... Volume is Length by Width by Height : To convert Volume, remember that ... (ie once each for length, width and height)

### If the volume of a box is 357, how do you determine length ...

If the volume of a box is 357, how do you determine length, width and ... length_____ width 14 height 11 surface area_____ volume 2029.72 length*width*height ...

### Edurite.com - How to Find the Height of a Rectangular Prism

To be able to understand how to find the height of a rectangular ... Find the height of a rectangular prism with volume = 70 cm 3 ... Length or Width or Height, ...

### Dimensions - PLATT ELECTRIC SUPPLY

Volume 2—Commercial Distribution CA08100003E ... (717.3) 22.42 (569.5) 14.06 (357.1) FR57P 14 9.34 ... Dimensions Height Width Length FR818N 26 37 ...

### CHAPTER 1 - BASIC TERMS AND CALCULATIONS

CHAPTER 1 - BASIC TERMS AND CALCULATIONS. ... The height (h), base (b), width (w), length (1) ... Volume (V) = length x width x height = 5 m x 10 m x 2 m = 100 m 3.

### Find what are the possible dimensions of a box volume 357?

Find what are the possible dimensions of a box volume 357? ... just do length x width x height You could measure the length, width, and height of the box and multiply ...

### How to find length of object with width - The volume of a ...

... length w is the width and h is the height the volume of the rectangular solid in the illustration is 357 cubic centimeters find the width ... is given by the ...

### Baseline dimensions of the human vagina - Oxford Academic

... age with pelvic flexure width and the height with width at the ... volume (3.0 ml versus 5.0 ... vagina vary along its length. The width of the vagina is ...

## Suggested Questions And Answer :

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### find the center of mass of the solid of uniform density biunded by the graphs of the equations

x^2+y^2=a^2 is a cylinder with its circular cross-section in the x-y plane; the cylinder is sliced at an angle by the plane z=cy, forming a wedge. y=0 is the x-z plane and z=0 is the x-y plane; these planes and the conditions that y and z are positive impose further constraints on the shap

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### The volume of rectangular bar is 640 cubic units. The width is 3 units more than the height and the length is 1 unit more than three times the height. Find the dimensions of the bar.

Let the night be H, then width=H+3 and length=3H+1, so volume=640=H(H+3)(3H+1). H(3H^2+10H+3)=640; 3H^3+10H^2+3H=640, or 3H^3+10H^2+3H-640=0. By a bit of trial and error, we can find that H=5 satisfies the equation, so we can use synthetic division to reduce the cubic to a quadratic: 5 | 3

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### Using the numerical technique, calculate the volume under the plane z=ax^2+by and over the rectangle R={(x,y):0≤x≤3 and 1≤y≤2}.

The usual way to solve this is by using double integrals. The volume is given by the summation of zdxdy, which is the volume of a tiny cuboid with length z, width dx and height dy. The limits are those of the rectangular width and height. For the purposes of illustration S will be used as the int

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### A box in the shape of a rectangular prism has a volume of 2500cm^3.

The volume is length times width times height=x(x+5)x/4=2500. Multiply through by 4: x^2(x+5)=10000 x^3+5x^2-10000=0=(x-20)(x^2+25x+500). The quadratic doesn't factorise, so x=20. Width=20cm, length=25cm, depth=5cm.

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### what is the maximum size of the volume of a 8.5inches x 11inches paper

The total surface area of a cube is 6a^2, where a is the length of its side. A cube produces the maximum volume. If the area of the paper is completely used to form a cube 6a^2=11*8.5 and a=3.9476". The maximum volume is a^3=61.52 cu in approx. If, however, the area of the paper could be used to

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### A box is to be made from a 12 by rectangular piece of aluminum by cutting 3x inches square from each corner. Express the volume of the box as a function of X,and find the domain

The cutouts reduce the length and width by 6x each: 12-6x and W-6x where W=width (not given). The height of the box is 3x when the sides and ends are folded up. The volume, V=3x(W-6x)(12-6x)=3x(12W-6xW-72x+36x^2)=36xW-18Wx^2-216x^2+108x^3=108x^3-18x^2(W+12)+36xW=18x(6x^2-(W+12)x+2W) cubic inch

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### volume of a solid bounded by the gragh of the equation √(x/a)+√(y/b)+√(y/c) =1 and the coordinate planes

I read the equation as √(x/a)+√(y/b)+√(z/c)=1 √(z/c)=1-√(y/b)-√(x/a) and z/c=(1-√(y/b)-√(x/a))^2. If we consider a cuboid (rectangular prism) of height z and length and width dx and dy, then the volume of the cuboid is zdxdy. The double integral will be ∫∫zdxdxy, representi

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### Use a right hand riemann sum to approximate the integr based off the values in the table. Integral from 0 to 14 of f(x) dx Table: (0,-1), (3,-2), (5,-1), (9,0), (13,-1), (14,0)

The Riemann sum is based on a simple concept: approximating the area under a graph using rectangles. The area of a rectangle is length times width, so width is the difference between two close values of x while length, or height,  is either the value of the function for the lower value of x or

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### b.Choose an appropriate length, width, and height for your package so that it can fit the product that you’re shipping. Using these dimensions, what is the ratio of surface area to volume?

SA/Vol=2(LW+LH+HW)/LWH=2(1/H + 1/W + 1/L). If all three dimensions are the same (cube) then the above expression comes to 6/X where X is the side length. This is the same as 6X^2/X^3, which is the area of 6 square faces divided by the volume.  To answer the question we need to know the di

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### how many 1/2" candies will fit in a 41/2" x 4" bowl?

Assuming that 4" is the height of the bowl, we can conclude that it is ellipsoidal, like a rugby football, with the shorter axis (x axis) being 4.5" in diameter and its longer axis (y axis) needing to be determined from the given figures. Two domes are cut off each end of the ellipsoid leaving a 3.5

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