which is greater, 2.6 or 2.60?


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which is greater, 2.6 or 2.60?

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which is greater 0.6 or 0.60 - Brainly.com


Which is greater 0.6 or 0.60 2. Ask for details ; Follow; Report; by jeruken 10/29/2015. Log in to add a comment Only registered members have access to verified answers
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Which is greater, 0.6 or 0.60? - Brainly.com


Which is greater, 0.6 or 0.60? 2. Ask for details ; Follow; Report; by MamaKaz 09/07/2016. Log in to add a comment Only registered members have access to verified answers
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What is greater 2/6 or 2/3? - Weknowtheanswer


What is greater 2/6 or 2/3? Find answers now! No. 1 Questions & Answers Place. More questions about Science & Mathematics, Mathematics, what
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What fraction is bigger? • Math Forum


... as you can see it by writing some multiplies of both 2 and 5 as shown below: 2 = 2, 4, 6, 8, ... 3 / 5 = 0.6 and 4 / 6 = 0.66667 so clearly 4 /6 is greater.
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Which is greater 2.6 or 2.36 - Answers.com


Which is greater 2.6 meters 26000 centimerters? 26,000cm > 2.6m 7 people found this useful Edit. Share to: Neodarwinian. 16,472 Contributions.
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Comparing fractions with > and < symbols (video ... - Khan ...


Comparing fractions with > and < symbols. ... So, once again, we could write 3/4 is greater than 2/4. And then finally, I encourage you to pause the video.
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book6 greater less - ALEX - alex.state.al.us


- 2 - Greater Than, Less Than, ... 6. 2 1 7. 6 8 8. 9 2 9. 3 3 10. 10 6 11. 7 10 ... 60 35 29 48 54 55 37 53 ...
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Compare Fractions: Equal Denominator | CoolMath4Kids


Compare Fractions: Equal Denominator. Page 1 of 3. Here's the problem: ... Which is greater: or ? Remember that the denominator tells us how many pieces something ...
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Greater than Calculator | [email protected]


Example problems on Greater than Comparison Back to Top. Is -5 greater than -2? Step 1 : On number line, -2 is allocated on right sideof -5, so -5 is not greater than -2.
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n^3-9n^2+20n prove that it is divisible by 6 for all integers n greater or equal to 1

Factor the given expression.   We have: n³-9n²+20n=n(n-4)(n-5) ··· Ex.1 If Ex.1 is divisible by 6, Ex.1 is also divisible by two prime factors of 6, 2 and 3. (6=2x3) A. If n is odd, (n-5) is even.   If n is even, (n-4) is also even.   Therefore
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how many ways can you have coins that total 18p using 1p , 2p, 5p, and 10p coins

in how many ways can you have coins that total exactly 18pence using 1p, 2p, 5p and 10p coins but you may wish to use as many of each sort as you wish. Start with the biggest coin, then the next biggest, etc. This is so that you always end up adding on just single coins of 1p. 10   &
Read More: ...

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Write an inequality and provide a value that may or may not be a solution to the inequality.

  x^2-3x-4>0 is an example of an inequality. (x-4)(x+1)>0; for this to be true the two factors must be both positive or both negative. Both positive: x-4>0, x>4; x+1>0, x>-1. So x must be greater than 4 because 4>-1. Both negative: x-4<0, x<4; x+1<0, x<
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Will a graph y = [x] ever have points in Quadrants III and IV? Explain.

Quadrant III is where x values are negative and y values are negative. If x = -3 and y = x, then y = -3, giving us the point (-3,-3), which is in quadrant III. Yes, y = x will have points in quadrant III. . Quadrant IV is a more interesting question. Quadrant IV is where x values are positive a
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how do you solve -x(x-5)(x+5)=0

-x(x-5)(x+5)=0 -x = 0 or x - 5 = 0 or x + 5 = 0 x = 0 or x = 5 or x = -5
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a, b, c are real numbers. such that a^2+b^2+c^2 = 1. prove that 1/2≤(ab+bc+ca)≤1

a^2 + b^2 + c^2 = 1 a, b, and c each have to be <=1 because if either was greater than 1, then a^2 + b^2 + c^2 > 1 a, b, and c each have to be >= -1 because if either was less than -1, then a^2 + b^2 + c^2 > 1 What we have now is:  -1 <= a, b, c <= 1 ab, bc, ca each have t
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is 0.794 greater than or less than 0.05

You can put any zeroes to the begginning of the number before the dot, and you can put any zeroes after the end of the number after the dot. 0.05 = 0.050 = 0.05000000000000000000000 0.794 = 0000000000.794 =00.794000000000 Now you can place the numbers in a way that the dots will be on top of eacho
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inequalities with less than or greater than symbol

(x-3) / (x+2) >= 0 There are two points to consider: x - 3 = 0 >> x = 3 x + 2 = 0 >> x = -2 Number line: <-----(-2)-----(+3)-----> Let's try something to the left of -2: (x-3)/(x+2) when x = -3 (-3-3)/(-3+2) (-6)/(-1) +1 1 is >= 0, so that section is in. Let's try
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((5)/(x-1)) - ((2x)/(x+1)) is less than 1

((5)/(x-1)) - ((2x)/(x+1)) < 1 ( 5(x+1)-2x(x-1) ) / (x^2 - 1) < 1 ( 5x + 5 -2x^2 + 2x ) / (x^2 - 1) < 1 ( -2x^2 + 7x  + 5 ) / (x^2 - 1) < 1 -2x^2 + 7x + 5 = 0 x = (-7 +- sqrt(7^2 - 4(-2)(5)) / 2(-2) x = (-7 +- sqrt(49 + 40)) / -4 x = (7 +- sqrt(89)) / 4 x = (7-sqrt(89))/4, (
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Find the solution set for each rational inequation. Graph the solution set on a number line.

(x+3)(x-2)/((x+2)(x-1))≥0. We need to look at various intervals marked by -3, -2, 1, 2 on the number line. x≤-3 satisfies the inequality; -3 Read More: ...

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