In a 50 marks non minus exam what's the probability of a student's gettin 30 or 35 marks ?

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# In a 50 marks non minus exam what's the probability of a student's gettin 30 or 35 marks ?

What's the probability of a student's getting 30 or 35 marks in a 50 marks exam where no minus marking is done.

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### In a 50 marks non minus exam what's the probability of a student's gettin 30 or 35 marks ?

1. how dum are the students? 2. dont yuno modern skuels kant fael NE student??? that wood impli sumthun rong with skuel (guvt) kant let talk like that start

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### There are 10 girls and 20 boys in a class. If half of the girls and half of the boys have blue eyes. Find the probability that one student chosen as moniter is either a girl or have blue eyes?

If a student is chosen at random we have 4 possibilities: Boy blue eyes (10) Boy non-blue eyes (10) Girl blue eyes (5) Girl non-blue eyes (5) The probabilities associated with these are: 10/30, 10/30, 5/30, 5/30; or 1/3, 1/3, 1/6, 1/6. There are 15 students with blue eyes and there

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### A survey group of 5 students are chosen at random from 25 elementary students and 13high school students. Determine the probability that at least 2 students chosen are elementary students.

There are 38 students in total. The probability, p, of choosing an elementary student=25/38, and the probability of not choosing an elementary student, 1-p,  is 13/38. This is a binomial situation expressed by (p+(1-p))^5 (=1, certainty) which expands to: p^5+5p^4(1-p)+10p^3(1-p)^2+10

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### how to calculate pass mark if 60% of students pass

If 60% of 100 students passed, then 60 students passed. Let's say the pass mark was 45%, then it means that 60 students scored 45% or more. If the pass mark was 67%, then 60 students scored 67% or more.  The number of students obtaining a pass is not directly related to the pass mark.

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### in a recent survey, the following data were obtained in response to the question

7 students out of 58 have no opinion, so probability=7/58=12.07%. Probability of being a freshman is 28/58 and probability of a random student answering no is 7/58, so the chances of one or the other is 28/58+7/58=35/58=60.34%. 24/58=41.38% is the probability of a sophomore favouring the issue. S

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### If N is 1200, Mean is 55, S.D. is 10, Find , 80% of students are to be promoted, what should be the marks for promotion

If X is the number of marks required to be included in the 80%, and the mean is 55 with SD=10, we have the z score=(X-55)/10. Any score below X puts the student in the excluded 20%. The value of z corresponding to 0.2 is approximately -0.84, so X-55=-8.4, making X=46.6 or 47 to the nearest

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### How can you get a probability of |X - 10|>1.8? given X~N (10,4)

Mean=10, SD=4. X-10>1.8, X>11.8 or 10-X>1.8, X<8.2. Convert to Z inequality: |X-10|>1.8, |X-10|/4>0.45, |Z|>0.45 means Z>0.45 or Z<-0.45. Z=(11.8-10)/4=1.8/4=0.45. This Z score corresponds to probability of 0.6736 (67.36%). But this probability is for Z<0.

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### how we get that -0.84 value

If X is the number of marks required to be included in the 80%, and the mean is 55 with SD=10, we have the z score=(X-55)/10. Any score below X puts the student in the excluded 20%. The value of z corresponding to 0.2 is approximately -0.84, so X-55=-8.4, making X=46.6 or 47 to the nearest

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### 4 poems by Shakespeare, 5 poems by Coleridge, 2 poems by Tennyson,

20. The two box-and-whisker plots below show the scores on a math exam for two classes. What do the interquartile ranges tell you about the two classes? (1 point) (0 pts) Class A has more consistent scores. (1 pt) Class B has more consistent scores. (0 pts) Overall class A performed better than cla

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### whats are all the zeros of 4x^5+28x^4-21x^3-147x^2+27x+189

Divide the quintic by 4: x^5+7x^4-21x^3/4-147x^2/4+27x/4+189/4. The factors of 189 are 3*3*3*7. So we could have as factors 3, 3/2, 3/4, 7, 7/2, 7/4. These are tentative solutions for x without taking account of the sign. To get + from 5 factors we have five pluses, 3 pluses and 2 minuses, 1 pl

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