How do you solve for (X) in this quadratic equation, 3X^2/(X^2-1)=4/(X-1)

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# How do you solve for (X) in this quadratic equation, 3X^2/(X^2-1)=4/(X-1)

solve by the use of factorization

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### Quadratic Equation Solver - Math is Fun

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### 2/×+2+4/×-5=28/(×+2)(×-5)

If you mean 2/(x+4) + 4/(x-5) = 28/( (x+2)(x-5) ) then: Multiply both sides by (x+4)(x+2)(x-5) 2(x+2)(x-5) + 4(x+4)(x+2) = 28(x+4) x(x^2 - 3x - 10) + 4(x^2 + 6x + 8) = 28x + 112 x^3 - 3x^2 - 10x + 4x^2 + 24x + 32 = 28x + 112 x^3 + x^2 + 14x + 32 = 28x + 112 x^3 + x^2 - 14x - 80 = 0

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A quadratic equation in the standard form is given by ax 2 + bx + c = 0 where a, b and c are constants with a not equal to zero. ...Solve the above equation to find the quadratic fomulas Given ax 2 + bx + c = 0 Divide all terms by a x 2 + (b / a) x + c / a = 0 Subtract

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### solve for x when (.182+x)/(.106-2x)=3.24

solve for x when (.182+x)/(.106-2x)=3.24 Im trying to solve for x its for a chemistry equation but i need to solve for x using the quadratic equation and i dont know which equals a b and c to find x. ************************** You can't solve this with the quadratic formula, because there is no x^2

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I think you may have typed this in wrongly because the term 2^x is not a permitted term in a quadratic equation. As it stands the solution to the equation is about -3.6168. Let's say you made a mistake in typing and the middle term is 2*x or 2x, then the solution exists but it is irrational (i

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Yes, sometimes factoring doesn't work. That's when we fall back on the quadratic formula. 4x^2 + 5x - 6 = 0 This is in the general form, y = ax^2 + bx + c. From that, we extract the values we need when we use the quadratic formula.        -b ± sqrt(b^2 - 4ac) x = ----

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3x + 6y – 6z = 9 2x – 5y + 4z = 6 -x +16y + 14z = -3 what is the answer how do you solve it and what are the answers ? 1)  3x + 6y – 6z = 9 2)  2x – 5y + 4z = 6 3)  -x +16y + 14z = -3 The first objective is to eliminate z so we can solve for x and y. It's a multi-step proces

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### Find the orthogonal canonical reduction of the quadratic form −x^2 +y^2 +z^2 −6xy−6xz+2yz. Also, find its principal axes, rank and signature of the quadratic form.

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26r-2=3r^2. The standard quadratic form is ax^2+bx+c=0, where x is the unknown and a, b and c are numbers. The unknown is r in this problem, so let's put the equation into quadratic form: 3r^2-26r+2=0. Note the sign changes as terms are transferred from one side to another, and also note that,

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Question:  Solve the equation p^2+p(x+y)+xy=0. Its related to engineering math -  Clairaut's equation. Since Clairaut's equation is a differential equation, then I am assuming that p means the first differential, dy/dx, or y'. You equation actually then is: (y')^2 + (y')*(x+y) + xy =

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