Prove the identity: (cosx + cosy)^2 + (sinx - siny) ... (cosx + cosy)^2 + (sinx - siny)^2 = 2 + 2 cos (x+y). 1. Ask for details ; ... (cos x +cos y)^2+(sin x-sin y)^2
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Suggested Questions And Answer :
Prove that G has exactly gcd(m,n) elements a such that a^m = e.?
Could I see how your teacher proved the original problem to see the clue? Read More: ...
Prove that x ± y = b?
looking back the basic concepts of analytic geometry..we can say that x+-y=b if and only if the slope interception is being decline by the two roots of the function of x...its too complicated but..its impossible to prove that equation. Read More: ...
Question: Prove the identity (sin alpha-cos alpha +1)÷(sin alpha + cos alpha -1)=(sin alpha + 1)÷(cos alpha).
Cross-multiply, to get
(sin(α) – cos(α) + 1)*cos(α) = (sin(α) + cos(α) – 1)*(sin(α) + 1)
Multiplying out and re-arranging,
sin(α).cos(α) – cos^2 Read More: ...
if u=f(r) prove that
if u=f(r) prove that
f is a function of r, and r is a function of x and y.
use r_x and r_y to denote the (partial) differentials of r wrt x, and wrt y, etc.
use f' and f'' to deno Read More: ...
how to prove sum of complex numbers z is zero when z^3=1
QUESTION: how to prove sum of complex numbers z is zero when z^3=1.
I think that what you want is to show that the sum of the roots is zero.
The cubic equation f(z) = z^3 - 1 = 0 has three roots, z1, z2, and z3 s.t. z1^3 =1, z2^3 = 1 and z3^3 = 1.
We wish to show that z1 + z2 + z3 = 0.
W Read More: ...
Use principle of mathematical induction to 3 prove that n3 —n is divisible by 3
Let p(n) = n3 - n
i)If n=1 , p(1 ) = 1^3 - 1 [ 1^3 means 1 cube ]
= 1 - 1
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Prove that if matrix A has an eigenvalue. ‘^ then matrix A^K (The k^th power of A)
prove that if a no. is a triplet than its 7 times. the cube root of the given no. Read More: ...
What is the most accurate value of pie ?
Unfortunately, your answer isn't correct because pi starts 3.14159... You can find pi to a large number of decimal places by Googling it on the Internet. It has a decimal which goes on forever never repeating and is classed as a transcendental number and it's irrational. Read More: ...