square root of 4489?

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# square root of 4489?

sqare root of 4489?

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### Square Root of 4489 - Easycalculation.com

What is Square Root of 4489 ? The square root of 4489 is an odd, 2 digit prime number 67. It is the 19 th prime number.
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### What is the square root of 4489 - Answers.com

The square root of a number is the factor which when multiplied by itself is equal to that number. i.e. 2 X 2 = 4, so 2 is the square root of 4.

### Square Root Of 4489 Simplified? - Math Question [SOLVED]

Simplify square root of 4489 in radical form? What is the square root for the number 4489. Learn how to simplify square roots into radical forms.
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### Find the square root of 4489 by factorization method ...

Find the square root of 4489 by factorization method meritnation.com. Purchase. 011-40705070 or . Call me . Select ... find square root by long division method. 16 ...
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### Square root of 4489 using prime factorisation - Brainly.com

Square root of 4489 using prime factorisation - 1662422. 1. Log in Join now Katie; a few seconds ago; Hi there! Have questions about your homework?
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### Square And Square Roots Class Eight Mathematics CBSE Maths

Square And Square Roots. Exercise 4. 1. Find the square root of each of the following numbers by Division method. (i) 2304 (ii) 4489 (iii) 529 (iv) 3249
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### Square root of 4500 - Conversion Calculators

Find the square root of 4500. ''Square Root Calculator' with step-by-step solution using the Babylonian Method or Hero's Method. Square Root Table.
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### Shortcut to Find Square Root of a Number - Testbook Blog

Learn shortcut to find square root of a number. You can learn this quick easy trick in 2 minutes and save upto 5 minutes in bank exams.
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### list of perfect squares - Square Root Calculator

Perfect Squares and their Square Roots Perfect Square: Taking a positive integer and squaring it (multiplying it by itself) equals a perfect square.
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## Suggested Questions And Answer :

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### complete the square to find the x intercepts of the function

x^2 +14x+78 1 wae tu look at it...(x+7)^2 +29 or yuze quadratik equashun & get roots= -7+-5.385164807i  (komplex variabels)

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### how do I solve x2 -6x +6 = 0

x2- 6x  +6 =0 compare with ax2 + bx + c = 0 here a = 1; b = -6 ; c = 6; D = b2 -4ac    = (-6)(-6) - 4 * 1 * 6   = 36 - 24  = 12 [ It is not a perfect square, so, you cannot get roots what u imagined] Use below method; x = -b+ square root of D/2a &

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### zeros of 2x^6+5x^4-x²

All the powers of 2 are even so this 6-degree expression can be reduced to a cubic if we put y=x^2: 2y^3+5y^2-y. Putting this equal to zero to find the y zeroes: 2y^3+5y^2-y=0. This factorises: y(2y^2+5y-1)=0. Take the quadratic: 2y^2+5y-1=0 and rewrite it as: y^2+5y/2=1/2 by dividing through by

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### show that the function f(x)= sqrt (x^2 +1) satisfies the 2 hypotheses of the Mean Value Theorem

f(x) = sqrt(x^2 + 1) ; [(0, sqrt(8)] Okay, so for the Mean Value Theorem, two things have to be true: f(x) has to be continuous on the interval [0, sqrt(8)] and f(x) has to be differentiable on the interval (0, sqrt(8)). First find where sqrt(x^2 + 1) is continous on. We know that for square roots

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### how to solve this quadratic equation x^2-2^x-13=0

I think you may have typed this in wrongly because the term 2^x is not a permitted term in a quadratic equation. As it stands the solution to the equation is about -3.6168. Let's say you made a mistake in typing and the middle term is 2*x or 2x, then the solution exists but it is irrational (i

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### What is the y-coordinate of the endpoint in quadrant III.

The point (1,6) is one endpoint of a line segement that has a length of square root of 80 units. The other endpoint is in quadrant III and has an x-coordinate of -3. We can draw a right triangle using these two points, and use the Pythagorean theorem to find what we are looking for. The length of

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### solve : x^2+kx+m=0

Simplest solution: we know that x=1 is a solution so x-1 is a factor. In a quadratic the constant term is the product of the roots so m must be the other root. The x term is minus the sum of the roots, so k=-(1+m). 1st alternative solution: Divide the quadratic by x-1 or use synthetic division appl

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### sqrt(3a+10) = sqrt(2a-1) + 2

sqrt(3a+10)=sqrt(2a-1)+2 To remove the radical on the left-hand side of the equation, square both sides of the equation. (~(3a+10))^(2)=(~(2a-1)+2)^(2) Simplify the left-hand side of the equation. 3a+10=(~(2a-1)+2)^(2) Squaring an expression is the same as multiplying the expression by itself 2 t

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### how do i solve the quadratic equation 16x^2=25

This is a perfect square.  First set it equal to 0 by subtracting 25 from both sides 16x^2-25=0 Take the Square root of both terms Square root of 16x^2 is 4x Square root of -25 is 5 and -5 The factored form is (4x+5) (4x-5) If you set each of these equal to 0 and solve for x you get 4x+

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### How to Find Square Root

98=49*2, so sqrt(98)=sqrt(49)*sqrt(2)=7sqrt(2)=7*1.4142=9.8994 approx. There's another way using the binomial theorem. 98=100-2=100(1-0.02). sqrt(100)=10 so sqrt(98)=10(1-0.02)^(1/2) because square root is the same as power 1/2. (1+x)^n expands to 1+nx+(n(n-1)/1*2)x^2+(n(n-1)(n-2)/1*2*

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