find and graph and equation parallel to 3x-2y=6 and passing through (-2,-1)

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# find and graph and equation parallel to 3x-2y=6 and passing through (-2,-1)

give the whole equation or steps how to solve it

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### Find the equation of the line passing through \$(-2,6)\$ and ...

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How would i find an equation of a line passing through point B(-2,4) ... is 2 point lower on the graph in ... equation of a line parallel to 3x-2y=6 and ...

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### Algebra 2-1 Unit 3 Semester Review Flashcards | Quizlet

Algebra 2-1 Unit 3 Semester Review. ... The y-intercept of the line whose equation is 3x - 2y = 6 is-3. ... Find the slope of the line passing through the points ...

### Standard Form, Parallel/Perpendicular, and X/Y Intercepts ...

Start studying Standard Form, Parallel/Perpendicular, ... 6y = -12 and passes through (-6, 2) ... 3x - 2y = 2. Write in Standard Form Passes

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### write an equation of the line that passes through the given point and is parallel to the give line (6,8), y=-5/2x+10

Since we know the lines are parallel they must have the same slope. That is the first place to start. We know that the slope intercept form of a line is y=mx+b where m is the slope and b is the y itnercept Since we know the slope or m value we can start by writing this as y=-5/2x+b now w

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### find the equation of a line parallel to 6x-7y+14 passing through (-4, 8)

Finding such an equation is very easy, so study the method I use and learn it. Don't just take the answer. The best way to start is rewriting the given function in slope-intercept form. 6x-7y+14 = 0 (I'm assuming it's set equal to 0; you didn't specify!) --> 6x - 7y = -14 &nb

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If f(x)=-4x^2/9+2x/3 as it was in your previous question, f'(x)=-8x/9+2/3, and is the slope of the tangent for all x values. This slope is parallel to y=-2x+4 when -8x/9+2/3=-2, because the line and the tangent line must have the same slope of -2 to be parallel. a) The equation that has to be s

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### equation of the line Through (4, 8); parallel to the line passing through (5, 6) and (1, 2)

Find an equation of the line that satisfies the given conditions. Through (4, 8);  parallel to the line passing through  (5, 6) and (1, 2)

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### find and graph and equation parallel to 3x-2y=6 and passing through (-2,-1)

1. 3x-2y=6...-2y=6-3x, 2y=3x-6, y=(3/2)x-3...this giv slope=3/2 2. thru (-2,-1) tu get y-intersept: deltax=+2 deltay=slope*deltax=2*3/2=3 yintersept=-1+3=2 line: y=(3/2)x+2

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### what line passes through 1,2 and is parallel to the graph of the line y=3x+8

what line passes through 1,2 and is parallel to the graph of the line y=3x+8 y = 3x + 8     the slope is 3 y = mx + b b = y - mx b = 2 - 3(1) b = 2 - 3 b = -1 The equation is y = 3x - 1

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### Find the pts on the graph of z=xy^3+8y^-1 where the tangent plane is parallel to 2x+7y+2z=0.

Question: Find the pts on the graph of z=xy^3+8y^-1 where the tangent plane is parallel to 2x+7y+2z=0. The tangent plane to the surface z=f(x,y)=xy^3+8/y is given by 2x+7y+2z=D Where D is some constant. The equation of the tangent plane to the surface f(x,y), at the point (x_0 y_0 ) ca

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