x^2-x-20=0 factor please? is the answer (x-5)(x+4) its been awhile

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x^2-x-20=0 factor please? is the answer (x-5)(x+4) its been awhile

I can't remember how to factor. Do I need to use quadratic formula for this or can I just easily factor it? What method should I use to solve this? I don't remember how to do basic factoring...

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Algebra II Final Flashcards | Quizlet


x + 5 Mathway (Algebra) Factor. ... (maybe 0.315 or 32%) Solution.11 + .20 + .31 + 30 + .15 + 24 = 1 (or ... Find h when t = 5.5 s. Round your answer to the nearest ...
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Factoring Quadratics: The Simple Case (page 1 of 4) - Purplemath


Factoring Quadratics: The Simple Case ... Factor x 2 + 5x + 6. ... This is the answer: x 2 + 5x + 6 = (x + 2)(x + 3)
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Help! 14 points A dilation with center (0,0) and scale factor ...


... (0,0) and scale factor 0.5 maps (4, -10) to ... (10,-5.4) is the answer Comments; Report; 2 5 2. ... PLEASE!!!! consider triangle PQR what is the length side of QR?
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11. Factoring and solving equations - Wellesley College


Findthat x-I gives 13+3.12-4 -0. So x-1 isa factor of x3 + 3x2 - 4 . ... Exam& Solve x2-2x-3=0 for x. Method: Factoring. x2 - 2x - 3 = ... 4. x2 - (x-2)2x = 4 5. x=-4 ...
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Solving Quadratic Equations: Examples - Purplemath | Home


Solving Quadratic Equations: Examples ... Solve x 2 + x – 4 = 0. ... which means the quadratic could have been factored. But I've got my answer, ...
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Simplifying Rational Expressions - montereyinstitute.org


When x = 4, the denominator is equal to 0. Answer . ... the values of x and y that make the numerator equal to 0. Factor the ... x 3 – x 2 – 20x = 0 . x(x 2 – x ...
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9th Grade Homework Help - jiskha.com


please solve for either x or y: x/2 + y/4 = 7 ... 9th grade whats the answer for xsquare+12x+20=0 ... How do you factor this expression? 10x+15
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20D - Homework Assignment 1 - UCSD Mathematics | Home


MATH 20D Homework Assignment 1 ... y0= x2=y (2) y0= x2=y(1 + x3) (3) y0+ y2 sinx= 0 (4) y0= (3x2 1)=(3 + 2y) ... answer given in the back of the book.)
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Java 170 Midterm Flashcards | Quizlet


Java 170 Midterm. OCC Spring 2011. ... Make sure that your answer is the correct type: 2 is an int 2.0 is a double ... 53 / 5 / (0.6 + 1.4) / 2 + 13 / 2. 8.5.
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Suggested Questions And Answer :


(2x+1)(3x-1)=0

(2x+1)(3x-1)=0 can u please show me the steps to solve this problem thanks The first impulse would be to multiply those quantities, but that would be a waste of time, because you would then need to factor the result. You already have the factors staring you in the face. What the problem is telling
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2x^3+16x^2+32x=0

4x^2-32x+16=0
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solve x²+7x+12= 0

solve x²+7x+12= 0 I need to know how to work it out - please help!!!!! x² + 7x + 12 = 0 We need to find factors of 12 that add up to 7. They must be 3 and 4 (x + 3)(x + 4) = 0 One, or both, of those factors on the left must equal zero. (Multiplying by zero produces a zero result.)
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(2x^2+x-6)/(x+2)=

2x^2+x-6 factorises: (x+2)(2x-3) so we have (x+2)(2x-3)/(x+2). There is a common factor in the denominator and numerator: x+2, so divide them by this common factor: 2x-3 is the answer. There's just one thing: you can only divide through by a common factor if the factor isn't zero, in other words x+2
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f(x)=x(x+2)(3x-3)/(x-4)(x+3) find x-int,y-int,vertical,horizontal asymotote

Fortunately the function has been factorised for us, so we can see what values of x in and outside the bracketed factors are needed to make those factors zero. That's a good start for answering the question, which appears to be a long-standing one. The values of x that produce zero factors are: 0, -
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Write the polynomial in factored form. x^3 + 7^2 + 15x + 9

If you mean x^3 + 7^2 + 15x + 9 then: x^3 + 49 + 15x + 9 x^3 + 15x + 58 does not have any rational zeros. (can't factor) If you mean x^3 + x^2 + 15x + 9 then: . . .it also appears to not have any rational zeros. If you mean x^3 + 7x^2 + 15x + 9 then: Let's try -1. . . f(x) = x^3 + 7x^2 + 15x
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x^2-x-20=0 factor please? is the answer (x-5)(x+4) its been awhile

x^2-x-20=0  if X^2  + aX + b = 0 then ; product of roots is b sum of roots is a there you have to look for numbers whose sum is a and product is b in the equation we have x^2-x-20=0 it can be easily seen that -5 + 4 = -1 -5 * 4 = -20 then we sh
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factor using the trial-and-error method: 12x squared - 5x -3

We need to be careful with this function, because it's quadratic and therefore it could have two roots, two solutions for x when the function=0. These solutions determine the factors. If we plot the graph of the function roughly we can see that when x is large and positive or negative, the function
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i need help with these questions please and can u explain how u got the answers to please??

x^2-x-4=0 me yuze Quadratik equashun zeroes: 2.5615528 & -1.5615528 a=1, b=-1, c=-4 b^2-4ac=17, so sqrt(17)=4.123105626 -b/2a=0.5 root/2a=2.061552812808 tell teech tu giv a problem weer anser be sumthun simpel, like 2
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factor 2x^3-2x^2-12

factor 2x^3-2x^2-12   I used syntetic division to find a factor.  remember that there is a 0x in the equation 2 |  2     -2     0     -12    |         -4  &nb
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