Problem of the Week Cutting Challenge Grade 5 Problem 23
Tim had 4 paper fraction pieces, each of thirds, fourths, sixths, and twelfths. He did not have enough pieces to show both 2/4 and 1/3 as equivalent fractions with the same denominator. How could he form enough pieces by making 1 cut with a scissors?
My daughter had this problem and for Read More: ...
how do you do fractions like say 4/9 in to 1/3 please tell me please!
"ELIZABETH WAS IN CHARGE OF COUNTING THE VOTES FOR CLASS PRESIDENT.CASEY RECIEVED 8/15 OF THE VOTES .HIS OPPONENT JASON RECIEVED THE REST OF THE VOTES.WHAT PARTS OF THE VOTES DID JASON RECIEVE?WHO WON THE ELECTION?"
Casey received 8/15 of the votes and Jason received the rest.
Since the deno Read More: ...
how can you get the answer 7 while only using the number 2,0,1, and 2?
My there brethren and standing hear today, it just because what DR. UWA has done me for me with problem of my husband. Contact him at: [email protected]. I am using this opportunity to share the testimony of what DR. UWA has done, he help me in such away that I didn’t no now to thank him Read More: ...
the area of a garden is 48 m2 , what is the greatest perimater the garden could have?
Problem: the area of a garden is 48 m2 , what is the greatest perimater the garden could have?
please help im stuck im in grade 5
The counter-question has to be, how unreasonable do you want to be?
Here are several pairs of numbers that give the designated area:
W,L 2W &n Read More: ...
You need to see through the problem and apply whatever is necessary to reduce the number of variables till eventually there's only one to find.
Remember a simple fact: if you have two variables you always need two independent equations to find them; for three variables, three equations; four variabl Read More: ...
I read this as (12x^3-48x^2-75x-24)/(6x+3). Divide top and bottom by 6: 2x^3-8x^2-12.5x-4)/(x+1/2).
We can use synthetic division:
-1/2 | 2 -8 -12.5 -4
.........2 -9......-8 | 0 = 2x^2-9x-8
Provided x≠-1/2 the quotient is 2x^2-9x-8 which is a simplification o Read More: ...
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