How do i solve for x: 1/4 = 8^(x+3)

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Guide :

# How do i solve for x: 1/4 = 8^(x+3)

I think I need to use Log, but how?

## Research, Knowledge and Information :

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## Suggested Questions And Answer :

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### 8x3-2x2=16x+4

The answer is x=1. You would first solve the problem on the left, leaving you with 20. Then, subtract the four from the right, to isolate the 16x, and subtract it as well from the 20 on the left. Leaving you with 16. Divide each side by 16, to isolate the x. Leaving you with 1=x.

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### 17x3 + (3x + 8x3)

???????????? "17x3"   iz zat spozed tu be 17x^3 ??????????????? and then add  8x^3 ?????????? sum=25 x^3

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### how to solve this expression 8x3+64y3 with the help of formula a3+b3=(a+b)(a2-ab+b2)

Let a=2x and b=4y. a^3+b^3=(2x+4y)(4x^2-8xy+16y^2)=8(x+2y)(x^2-2xy+4y^2)=8x^3+64y^3

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### How do I solve y=-x-4

How do I solve y=-x-4 I need to be able to plot these points on a graph but i don't know how to solve the problem.   make an x & y axis. ( like a cross one line goes vertical an the other horizontal) put equal dimention for x & y line From center line moving

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### how to solve for x with fractions

Simplifying x3 + 3x2 + -4x = 0 Reorder the terms: -4x + 3x2 + x3 = 0 Solving -4x + 3x2 + x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(-4 + 3x + x2) = 0 Factor a trinomial. x((-4 + -1x)(1 + -1x)) = 0 Subproblem 1 Set the factor 'x' equal to zero an

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### How do you solve this problem? solve for d: n= m+3d/4

Problem: How do you solve this problem? solve for d: n= m+3d/4 I need help solving this and seeing how it was solved since I am having trouble figuring out what to do and how to solve it thanks. n = m + 3d/4 n - m = (m + 3d/4) - m n - m = 3d/4 4(n - m) = (3d/4)4 4(n - m) = 3d 4(n - m)/3 = 3

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### how can i solve these equations?

how can i solve these equations? x + 3y – z = 2 x – 2y + 3z = 7 x + 2y – 5z = –21 We eliminate one of the unknowns (x, y or z, take your choice), leaving two unknowns. Then, we eliminate a second one, giving us an equation with only one of the unknowns. Solve for that and plug that value in

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### Solve, using linear combination. 3x + y = 4 2x + y = 5

line 1: 3x+y=4    or y=4-3x line 2: 2x+y=5 line 1 -line2...(3x-2x)+(y-y)=4-5 or x=-1 y=4-3x=4+3=7

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### Inequalities

9x+6=51 9x=51-6 9x=45 x=5

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### x - z = -3, y + z = 9, -2x + 3y +5z = 33

Problem: x - z = -3, y + z = 9, -2x + 3y +5z = 33 1) x - z = -3 2) y + z = 9 3) -2x + 3y + 5z = 33 Add equation 2 to equation 1.      x     - z = -3 +(    y + z =  9) ------------------   x + y     = 6 4)

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