find the derivative of x + 2y = 20


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find the derivative of x + 2y = 20

find the derivative of x2 + 2y = 20

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What is the derivative of x^2y^2? | Socratic


... ("some function")^2]=2x*("some function")^2+x^2*2("some function")*"the derivative of the ... So d/(dx)(x^2y^2)=2xy^2+x^2 ... What is the derivative of #x^2y ...
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Online Derivative Calculator • Shows All Steps!


... for example we write "5x" instead of "5*x". The Derivative Calculator has to detect these cases and insert the ... For each calculated derivative, ...
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How do you find the derivative of sqrt(x^2+y^2)? | Socratic


... derivation with respect to x at constant y is an example of partial derivative: del/(delx)sqrt(x^2 ... do you find the derivative of #sqrt(x ... find #(d^2y)/ (dx ...
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What is the derivative of 2Y - Answers.com


Answers.com ® WikiAnswers ® Categories Science Math and Arithmetic Calculus What is the derivative of 2Y? ... 5x = 2y + 20 x = 2/5y + 4 Solve for y: ...
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Find Derivative of y = x^x. Classic - analyzemath.com


Find Derivative of y = x x. A calculus tutorial on how to find the first derivative of y = x x for x > 0.
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Implicit Double Derivatives: x^2 + y ^ 2 = 25 - Free Math Help


2) Find the second derivative of y = x^2 y^3 + xy I actually have no clue how to find the second derviative. ... Implicit Double Derivatives: x^2 + y ^ 2 = 25 1) ...
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Find The Derivative Of The Function. Y=x^4+10/x^2 ... - Chegg.com


Answer to Find the derivative of the function. y=x^4+10/x^2 A. d^2y/dx^2=2+60/x^4 B d^2y/dx^2=2x-20/x^3 C d^2y ... Find the derivative of the function. y=x^4+10/x^2 ...
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Derivative Calculator: Solve Derivatives with Wolfram|Alpha


Online Derivative Calculator Solve derivatives with Wolfram|Alpha: ... ^2 - 3x^2)/(h) = 6 x`. The derivative is a powerful tool with many applications. For example, ...
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SOLUTIONS TO IMPLICIT DIFFERENTIATION PROBLEMS


SOLUTIONS TO IMPLICIT ... and the first derivative as a function of x and y is (Equation 1) . To find y ... and the second derivative as a function of x and y ...
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real analysis - Did I take the derivative correctly? $x^y=y^x ...


Did I take the derivative correctly? $x^y=y^x$ ... 6,296 5 20 59. asked Nov 1 '13 at 20:49. ... Thus to properly compute the derivative, you have to rewrite $y^x = e^ ...
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can you please explain how to to find dy/dx for the function x^2 y+ Y^2 x = -2

I need to find dy/dx of this function and evaluate the derivative at the point (2,-1) x^2 y+y^2 x = -2 solve the equation to be  = 0 x^2y + y^2x +2 = 0 find partial derivatives for dy and dx, the first term has two parts x^2y has two partial derivatives 2xy dx + x^2 dy the
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the integral of xtanx dx

Consider the function tanx=a0+a1x+a2x^2+...+a(n)x^n where a(n) is the coefficient of x^n. We need to find a(n). We can do this by applying calculus (effectively Taylor's theorem). If we integrate tanxdx we get -ln(cosx). If we integrate the power series we get C+a0x+a1x^2/2+a2x^3/3+...+a(n)x^(n+1
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first derivative test

After you find the first derivative, set it equal to zero that will give you the potential candiates for absolute extrema. Then construct a sign chart of the first derivative for those numbers where you pick a number less than or between those numbers and then plug them into for x in the first deriv
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find the nth derivative of y=log(1+x)

Question: find the nth derivative of y=log(1+x). Using yn as the nth derivative, y = ln(1+x) y1 := 1/(1+x) y2 := -1/(1+x)^2 y3 := 2/(1+x)^3 y4 := -6/(1+x)^4 y5 := 24/(1+x)^5 By observation, we can see that the nth derivative will be given by yn = (-1)^(n-1).(n-1)! / (1+x)^
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Find the 1st and 2nd derivative of 3xy=4x+y^2 Differentiate both sides of 3xy=4x+y^2 implicitly. 3y + 3xy' = 4 + 2yy'  ----- (1) y'(3x - 2y) = 4 - 3y y' = (4 - 3y)/(3x - 2y)  ---- 1st derivative To get the 2nd derivative, it would probably be simpler to implicitly differenti
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(tanx-x)/(x-sinx)=(sinx-xcosx)/(xcosx-sinxcosx). As x approaches 0 the expression approaches 2. Why? To find out, let's use some calculus. Let's suppose that sinx=a[0]+a[1]x+a[2]x^2+a[3]x^3+...+a[n]x^n, a polynomial series in x, with real coefficients a[0], etc. We are going to use a value f
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Find the directional derivative of f(x; y; z) = 1/(√ x^2+y^2+z^2) at P : (3; 0; 4) in the direction of a = [1; 1; 1].

Find the directional derivative of f(x; y; z) = 1/(√ x^2+y^2+z^2) at P : (3; 0; 4) in the direction of a = [1; 1; 1]. The directional derivative is: Du.f(x,y,z) = fx(x,y,z).a + fy(x,y,z).b + fz(x,y,z).c,  where, f(x, y, z) = 1/(√ x^2+y^2+z^2) and u = (a, b, c) = (1, 1, 1) fx = -
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to find nth derivative of tan ^ ( - 1 ) ( x / a ) with solution

Let y=tan^-1(x/a), then tan y = x/a. sec^2(y)dy/dx=1/a so dy/dx=1/(a(sec^2(y))=1/(a(1+tan^2(y))=1/(a(1+(x^2/a^2))=1/(a+x^2/a)=(a+x^2/a)^-1 Write y'=dy/dx for convenience, so y'' is the second derivative and y'=(a+x^2/a)^-1 or sec^2(y)y'=1/a. Let u=v=sec y and w=y', then sec^2(y)dydx=1/a
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Given cos (x) cos(2x) cos(3x) let d/dx cos x = -sin x d^2/dx^2 cos x = -cos x d^3/dx^3 cos x = sin x and then things repeat, you get the same sequence of derivatives after that. If n is odd the nth derivative is: (-1)^( (n+1)/2 ) sin x And if n is even (-1)^( n/2 ) cos x d/dx cos 2x = -2 sin 2x So t
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find compelet derivative of y = ln(sinex))2 cos(tanx)

y = ln(sinex))2 cos(tanx) dy/dx=2(lnsinex*-sin(tanx)*secx^2+cos(tanx)*cosx*e/sinx)
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