i need help with finding the answer for the square root of 34

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# i need help with finding the answer for the square root of 34

i need help with finding the step by step answer for the square root of 34

## Research, Knowledge and Information :

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### Squares and Square Roots - Math is Fun

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### Calculate square root without a calculator

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### Numbers - Square Roots - In Depth - Math.com

... called "finding the square root." ... get as close as you can by finding two perfect square roots your number is ... (you can round off your answer) 3.

### Radicals: Introduction & Simplification | Purplemath

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### Square Root Calculator - Math.com

The Square Root Calculator will find the square root of the number you enter.

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### i need help with finding the answer for the square root of 34

The only step by step way of finding the square root of a number which doesn't radicalise is to use an arithmetic technique as follows: We know that the answer is close to 6 because 6 squared is 36, so there will be decimals. We write digits in pairs thus: | 34 |•00 | 00 | 00 | 00 The ans

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### Guyssss please help me "Create a problem situation in which only the positive solution is meaningful" what am I going to do? I can't understand it

First, you need to understand the question, right? You need to know what gives you more than one solution. The answer is an equation which contains a polynomial of at least degree 2. That means a quadratic equation or a cubic equation, or more, that has more than one solution. A typical example

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### How to Find Square Root

98=49*2, so sqrt(98)=sqrt(49)*sqrt(2)=7sqrt(2)=7*1.4142=9.8994 approx. There's another way using the binomial theorem. 98=100-2=100(1-0.02). sqrt(100)=10 so sqrt(98)=10(1-0.02)^(1/2) because square root is the same as power 1/2. (1+x)^n expands to 1+nx+(n(n-1)/1*2)x^2+(n(n-1)(n-2)/1*2*

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### zeros of 2x^6+5x^4-x²

All the powers of 2 are even so this 6-degree expression can be reduced to a cubic if we put y=x^2: 2y^3+5y^2-y. Putting this equal to zero to find the y zeroes: 2y^3+5y^2-y=0. This factorises: y(2y^2+5y-1)=0. Take the quadratic: 2y^2+5y-1=0 and rewrite it as: y^2+5y/2=1/2 by dividing through by

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### factor using the trial-and-error method: 12x squared - 5x -3

We need to be careful with this function, because it's quadratic and therefore it could have two roots, two solutions for x when the function=0. These solutions determine the factors. If we plot the graph of the function roughly we can see that when x is large and positive or negative, the function

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### Can you find the properties of this hyperbola? -4x^2 + y^2 - 8x - 12y + 36 = 0

4x^2/y^2+8x/y+16+12y/x+9y^2/x^2=0 find the square root ot this equation

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### Factoring perfect square trinomials

Numerically, a perfect square is a number that is the product of another number multiplied with itself ( 4 x 4 = 16.  16 is a perfect square). For trinomials, a perfect square trinomial is a trinomial that is the product of a binomial multiplied with itself  (   (2x-5)(2x-5) = 4

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### How do I find the limit as x approaches -.25 square root of (x+14)/x+3)?

EVALUATE (x+14) / (x+3) at x=-0.25 =(14-0.25) / (3-0.25) =13.75 / 2.75 =5

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### how do you find the domain of the composite function when the f(x)=sqrt of x and g(x)=2x-5

When we look at each function we can see that g is defined for all values of x as a linear function. It is represented by an infinitely long straight line. But f is the square root of g(x) when the two functions are combined. We can't find the (real) square root of a negative number so the domain mu

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### 10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into

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