the line passes through (7,-2) and is parallel to the line whose equation y=4x+2 is


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the line passes through (7,-2) and is parallel to the line whose equation y=4x+2 is

type the slope interception form of the equation of the line

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passing through (4,4) and parallel to the line whose equation ...


passing through (4,4) and parallel to the line whose equation is 2x+y-7=0. 0 votes. ... what line passes through 1,2 and is parallel to the graph of the line y=3x+8.
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What is the equation of the line that passes through (1,2 ...


What is the equation of the line that passes through #(1,2)# and is parallel to the line whose equation is #4x+y-1=0#?
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What's the equation of the line through (3,7) and parallel to ...


What's the equation of the line through (3,7) ... an equation for a line parallel to y=4x+2 and that is ... parallel to the line y − 1 = 4 (x + 3) and passes ...
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What is the equation of the line that passes through (1, 2 ...


What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y - 1 = 0? algebra 1 , functions . 7/10/2013 ...
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What is the equation of the line that passes through (2, -2 ...


What is the equation of the line that passes through (2 ... of the lines 4x+y-1=0 and ... the equation of a line parallel to y-3x+2=0 passing ...
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the line passing through (2,-2) and is parallel to the line ...


the line passing through (2,-2) and is parallel to the line whose equation is y=3x + 3. ... (-3,0) and (a) the line parallel that passes through the origin (b) ...
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Write Equation of Line parallel to a given line and point-- a ...


Write the Equation of a Line Parallel to a line and through a ... line that is parallel to another line and that passes ... equation of the line y = 3x + b. Step 2.
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equation for line

Problem: equation for line Write and equation for passing through (4,-1) and parallel to the line whose equation is y=-2x+3 First, we notice that the slope of the given line is -2. That will be the slope of the line we are trying to determine. Our equation: y = mx + b Using the co-ordinates
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Passing through (-4,4) and parallel to the line whose equation is y=3x+2

strate line thru point=(-4,4) with slope=3 y=3x+konst projekt line from x=-4 tu x=0...deltax=+4 deltay=slope*deltax=3*4=12 y=4+12+16 y=3x+16
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how do i solve this?

y = mx + b is the equation of a line.  m is the slope.  If you have two parallel lines, they will have the same slope, so m will be the same on both of them. In your case, you have y = -3x + 5, so m = -3 This means the parallel line will also have a slope of -3, so it's equation is y = -
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Find the equation of the cylinder having its base the circle

When z=1, x^2+y^2=4, which is a circle, centre at the origin and radius 2. x-2y=1 is a plane intercepting the x-y plane with y intercept=-1/2 and x intercept=1. The equation x^2+y^2+(z-1)^2=4 is a sphere, centre (0,0,1) and radius 2. The plane cuts through the sphere when (1+2y)^2+y^2=4; 1+4y+4y^2+y
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what is the slope of the line whose equation is y-5=3(x-2)

y-5 =3(x-2) y=3x -6 +5 y=3x-1 slope=3
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the line passes through (7,-2) and is parallel to the line whose equation y=4x+2 is

start: point=(7,-2) & slope=4 need tu get y-intersept...x=0 deltax=7, deltay=slope*deltax=28 y-intersept=-2 -28=-30 line: y=4x-30
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equation of the line Through (4, 8); parallel to the line passing through (5, 6) and (1, 2)

Find an equation of the line that satisfies the given conditions. Through (4, 8);  parallel to the line passing through  (5, 6) and (1, 2)    
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find the equation of a line parallel to 6x-7y+14 passing through (-4, 8)

Finding such an equation is very easy, so study the method I use and learn it. Don't just take the answer. The best way to start is rewriting the given function in slope-intercept form. 6x-7y+14 = 0 (I'm assuming it's set equal to 0; you didn't specify!) --> 6x - 7y = -14 &nb
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I need to see how you work this Wrote the equation of the line passing throught (4,1) and parallel to the line y=3x-2

parallel to y = 3x - 2 and passing through (4,1): Parallel lines have the same slope, so the slope is 3: using the equation (y - y1) = m(x - x1): y - 1 = 3(x - 4) y - 1 = 3x - 12 in slope-intercept form: y = 3x - 11 in standard form: 3x - y = 11
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How do I write an equation of the line that passes through the given point (-2,5), 2y=4x-6

When two lines are parallel they have the same slope but different y intercept. 2y=4x-6 can also be written y=2x-3 because 2 is a common factor to both sides. The slope of this line is the number before the x term=2. Now we can write the equation of the parallel line: y=2x+b, where we have to f
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