how to solve thi matrics by using gauss elimination[(x+y-z=0),(2x-y+z=6),(3x+2y-4z=-4)]


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how to solve thi matrics by using gauss elimination[(x+y-z=0),(2x-y+z=6),(3x+2y-4z=-4)]

my background is not mathematics

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Linear Algebra Answers - Scribd


This is Cramer’s Rule for the system x + 2y = 6, 3x + y = 8. ... x + y − z = 10 2x − 2y + z = 0 −→ x ... (x, y, z) = (5, 5, 0). (f ) Here Gauss’ method ...
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Linear Algebra - Solutions - Answers to Exercises Linear ...


Linear Algebra - Solutions - Answers to Exercises Linear... SCHOOL Indian Institute of Technology, Chennai; COURSE TITLE MATHEMATIC MA2030; TYPE. Homework Help ...
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Jim Hefferon - Linear Algebra - Answers to Questions - Documents


Share Jim Hefferon - Linear Algebra - Answers to ... This is Cramer’s Rule for the system x + 2y = 6, 3x + y ... Gauss’ method ρ1 ↔ρ4 x + y − z = 10 2x ...
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how to solve thi matrics by using gauss elimination[(x+y-z=0),(2x-y+z=6),(3x+2y-4z=-4)]

Matrix representation of problem: (  1 1 -1 | 0 ) (  2 -1 1 | 6 ) (  3 2 -4 | -4 ) In the following solution, only the rows that are changed are shown with each operation: R1+R2: ( 3 0 0 | 6 ); R1/3: ( 1 0 0 | 2 ); R2-2R1: ( 0 -1 1 | 2 ); R3-3R1: ( 0 2 -4 | -10 ); R3/2: ( 0 1 -2
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solve these equations using matrices without a calculator. x=y=z=6, 2x=y-4z=-15, 5x-3y+z=-10

x-y-z=6 2x-y-4z=-15 5x-3y+z=-10 Your equations, as written, had typos in them. I've assumed that some of the equal-signs should have been minus-signs and altered then appropriately. In matrix form the equations would be AX = b Where A is the matrix 1 -1 -1 2 -1 -4 5 -3 1
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What is matricx

A matrix is a rectangular or tabular representation of quantities. Like a table, it has rows and columns and each "cell" is called an element. Matrices can be combined using addition, subtraction or multiplication, provided certain rules are followed about the sizes of the matrices involved. A ma
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what is the answer to 2x-y-2z=1, 4x+y-z=5, x+y+4z=-5 using matrices

what is the answer to 2x-y-2z=1, 4x+y-z=5, x+y+4z=-5 using matrices how to solve this math problem using matrices?   2  -1  -2  │  1   4   1  -1  │  5   1   1   4  │ -5 Multiply line 2 by 2. &nbs
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x+2y-37=7, x+y+7=2, 2x-y+27=1

I assume that there is a missing z in each equation. If that is the case, the solution using matrices and determinants is x=255/119, y=67/119, z=-12/119. CHECK Plug these values into the original equations: (255+134+444)/119=833/119=7; (255+67-84)/119=238/119=2; (510-67-324)/119=119/11
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solve 6x+5y=13 and 3x-2y=-16 using matrices

solve 6x+5y=13 and 3x-2y=-16 using matrices. We can write down the equations as, 6x + 5y = 13 3x - 2y = -16 In matrix notation, the set of equations is written as, | 6   5 | | x |= | 13 | | 3  -2 | | y |   |-16 | or, AX = b The solution is given by:
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solve using matrices and row-reduction


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using gauss elimination what are the steps taken to solve 5x + 3y equal to 6 and 6x - 2y equal to 10

line 1...5x+3y=6 line 2... 6x-2y=10, or 3x-y=5, or y=3x-5 me dont no nuthun bout NE "Gaus Liminate" insted, plug line 2 intu line1...5x +3*(3x-5)=6 5x +9x -15=6 14x=6+15=21 x=21/14 x=1.5 y=3x-5...3*1.5 -5=4.5-5... x=-0.5 chek...5x+3y=6...5*1.5 +3*(-0.5)=7.5-1.5=6
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Can someone explain to me how to solve a 2x2 linear equation with matrices? and provide me with an example?

3 7 8 2 1 1  
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rewrite the equations as matrices, -19x=-4y+12, and 4y=-3x+100

rearrange the equations to become: -19x + 4y = 12 3x + 4y = 100 augmented matrix is: -19 4 : 12 3 4 : 100 Determinant A = -19*4 - 3*4 = -88 Determinant Ax (replace the x column with the constants) resulting matrix: 12 4 100 4 so Determinant Ax = 12*4 - 100*4 = -352 x = Determinant Ax / Determinant A
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