u buy100animals for$100 chicks 4 .10 & pigs 4 $2 & sheep 4 $5 how many of ea. can u buy to =$100


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u buy100animals for$100 chicks 4 .10 & pigs 4 $2 & sheep 4 $5 how many of ea. can u buy to =$100

please show the equation if you have 100 animals all cost different and total price is $100. oo not sure how to calculate how many of each to reach a combinded total of $100.00 and 100 animals please help!

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u buy100animals for$100 chicks 4 .10 & pigs 4 $2 & sheep 4 $5 how many of ea. can u buy to =$100

wen yu sae "chiks 4.10", du yu meen 1 chik kost 0.10$???? if so, 100$ bi 1000 chiks
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I have 75 sheep, 15 chicks & buy 3 more sheep how many more chicks can I buy to keep ratio same?

The ratio is 15/75 = 1/5 x/3 = 1/5 x = 1/5(3) x = 3/5 x = 0.6 of a chick Are you sure you typed the problem correctly? I seriously doubt that you can by 0.6 of a chick. (15 + 0.6)/(75 + 3) = 1/5 15.6/78 = 1/5 1/5 = 1/5   Problem statement: I have 75 sheep, 15 chicks & b
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I need help with math a lot. I have a test on cyber school remaining right now! Can you please hurry and get this done fast before 1 hour is up?

You haven't given a specific question, but, if it helps, you can write a ratio as a fraction. a:b is the same as a/b. You can "cancel down" a ratio just the same as cancelling down a fraction, by dividing a and b by a common factor. Examples: 7:28 is the same as 1:4; 21:35 is the same as 3:5; 27:45
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how to solve this word problem

A retailer incurs a fixed cost of N$ 330when purchasing sugar for his stock. He pays N$15.00 per packet which he resells at N$18.00 per packet. How many packets should he purchase and sell in order to break even? Let us suppose that he buys X packets. Then his costs are: X packets at $15
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or book in informston

yu got 2 many amps theer...gonna blo a fuze
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HELP MEEE Please :<

me assume "2x2" shood be 2*x^2 & similiar add 3 terms...5x^2 +9x...(10-7-3 bekum 0)
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Please answer soon! Algebra - show your work

Let n be the number of calculators so each one cost 240/n. She sold n-1 calculators for $300 so each calculator was sold for 300/(n-1). The profit=5=300/(n-1)-240/n. Multiply both sides of the equation by n(n-1): 5n(n-1)=300n-240n+240. So 5n^2-5n=60n+240. This is a quadratic equation: 5n^2-65n-240=0
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10.00X + .5X + Y = 100


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how many ways can you have coins that total 18p using 1p , 2p, 5p, and 10p coins

in how many ways can you have coins that total exactly 18pence using 1p, 2p, 5p and 10p coins but you may wish to use as many of each sort as you wish. Start with the biggest coin, then the next biggest, etc. This is so that you always end up adding on just single coins of 1p. 10   &
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what are the possible combination of making 30 with 1, 3, 5, 7, 9

I started off by figuring how many ways to use nines: 30   3 nines, 27 total   2 nines, 18 total   1 nine, 9 total   0 nines, 0 total I then figured how many ways to use sevens: 30   3 nines, 27 total     0 sevens, 27 total &nb
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